Hot answers tagged standard-deviation
Variance measures how spread out they are, so with five numbers, put two of them at the one endpoint and three at the other. Thus: $0,0,0,100,100$. With an even number of numbers, put have of them at one endpoint and half at the other. For $0,0,0,100,100$, the variance is $\left(\frac 3 5\cdot\frac 2 5\right)\cdot100^2$. (Here I am using $\frac 1 n ...
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