15 votes

List of geometric theorems linked by two squares

For now, I will only post pictures of the theorems. Perhaps later I will add links that talk about the theorems in detail Potema's theorem: Two squares created on the sides of a triangle $∆ABC$ And ...
زكريا حسناوي's user avatar
6 votes
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Maximizing area of the triangle in a quarter circle

The area of the triangle ABC is equal to its side AC multiplied by the height, divided by $2$. The height will be maximal if we draw a radius OB such that OB is perpendicular to AC. Let H be the ...
Aig's user avatar
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6 votes

Euclidean Geometry problem regarding the line passing through incenter

In fact, your existing work almost solves the problem already. The next step is to observe that the altitude $h_A$ from $A$ to $BC = x+y$ must satisfy $$5 \sqrt{2} = |\triangle ABC| = \frac{1}{2} h_A ...
heropup's user avatar
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5 votes
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Geometry problem with external tangent of two circles

Let us use inversion to show the following lemma, equivalent to the given problem: Lemma: Consider two circles $\odot(O)$, $\odot(O')$, intersecting in two points, $A,B$, and having $PQ$ as common ...
dan_fulea's user avatar
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4 votes

Is my trigonometric proof of the Pythagorean theorem correct?

The identity $\sin^2\theta + \cos^2\theta = 1$ is essentially the Pythagorean Theorem in the form of trigonometry. In your proof you use the fact that triangles with congruent angles are similar. This ...
David K's user avatar
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4 votes

List of geometric theorems linked by two squares

Euclid Book II Prop 6 on what we would now describe algebraically as the difference of squares:
Ethan Bolker's user avatar
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3 votes

Geometry problem with external tangent of two circles

Let O and W be the centers of $C_3$ and $C_2$, respectively. Notice that Y, O, W are collinear by the property of tangent circles. We'll mark $∠OZX = ∠OXZ = \alpha$ and $∠OZY = ∠OYZ = \beta$. ($OZ = ...
Meison's user avatar
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3 votes

Maximizing area of the triangle in a quarter circle

Just extend the circle, call $A'$ and $C'$ the intersection of the line AC with the circle. The middle $B$ of the arc $A'C'$ is the solution.
Letac Gérard's user avatar
3 votes
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Proving that the cone on a finite Euclidean simplicial complex is again a Euclidean simplicial complex.

This is proved in Munkres's Elements of Algebraic Topology book. Essentially, every point of $w\ast\sigma$ is on a unique line segment from $w$ to some point of $\sigma$. Thus a point in the ...
Steve D's user avatar
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Conjecture: The line joining the incenter and the circumcenter always subtends an obtuse angle at centroid

Denote the incenter by $I$, circumcenter by $O$, the centroid by $G$. Assume that the triangle is not equilateral, so that the points $I, G, O$ are distinct. In order to prove that $\angle IGO>90^\...
timon92's user avatar
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3 votes

Why is maximum number of joints of 6 lines is 4?

Note that $2$ intersecting lines define a plane. Thus, a joint is formed by $3$ intersecting planes. Let's add one more plane to these three. Note that $4$ planes have at most $6$ distinct lines as ...
Vasili's user avatar
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Why is maximum number of joints of 6 lines is 4?

Let $G = (V,E)$ be a graph, and we're interested in the vertices which fulfill $deg(v) \geq 3$. We notice that $|E| = 6$ from the assignment, and we can use your earlier fact that a tetrahedron is a ...
Eemil Wallin's user avatar
3 votes
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Distance between triangle incenter and vertices

I'm using $s$ for semiperimeter (that's more common). First, drop perpendiculars from $I$ onto $a,b,c$ and call them $ID,IE,IF$ respectively. All are equal to the inradius $r$. Then, it is well known ...
D S's user avatar
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3 votes

List of geometric theorems linked by two squares

Here are somewhat-natural generalizations of a couple of the two-squares-joined-at-a-vertex results from OP's answer. Potema's Theorem Let squares $\square A'B'C'D'$ and $\square A''B''C''D''$ be as ...
Blue's user avatar
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3 votes
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A triangle whose area is four times the area of ​Napoleon's triangle

The circumcircles of the outer equilateral triangles, centred at $L$, $M$, $N$, meet at $F$, the Fermat point of triangle $ABC$. Note that $LM$ is the perpendicular bisector of common chord $CF$, $MN$ ...
Intelligenti pauca's user avatar
3 votes

Euclidean Geometry problem regarding the line passing through incenter

You've made a good start. Using your diagram, we have that $$2\alpha + 2\beta + 2\gamma = 180^{\circ} \;\to\; \alpha + \beta + \gamma = 90^{\circ} \tag{1}\label{eq1A}$$ Thus, using your $x + y = 3\...
John Omielan's user avatar
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3 votes

What is the $\inf$ and $\sup$ of the area of quadrilateral given its sides length?

Areas can get arbitrarily small under some circumstances, suach as edges (in order) $a,b,a,b$ which has maximal area as a rectangle, but can be squashed down as a parallelogram. The example that ...
Will Jagy's user avatar
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3 votes

What is the $\inf$ and $\sup$ of the area of quadrilateral given its sides length?

The supremum will be when the four nodes lie exactly on a circle: a cyclic quadrilateral. The area of a quadrilateral inscribed in a circle is given by Bretschneider’s formula (actually Brahmagupta's ...
Rich's user avatar
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2 votes

Is my trigonometric proof of the Pythagorean theorem correct?

It is neither right nor wrong , though it is useful to improve basic intuition. Euclidean Geometry ( with the list of Axioms & Postulates including the Parallel Postulate ) gives the Pythagorean ...
Prem's user avatar
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2 votes

Generalizing the property of two parabolas tangent to a circle, each of which touches it at two points

Still not an answer, but I would like to share a generic SAGE program (SAGE is a free Python-like online resource ; see below this program and the way to run it). Writing this program has in fact be ...
Jean Marie's user avatar
2 votes

How many intersections are there for two confocal parabolas with their axis perpendicular to each other?

The polar equation of a parabola opening upward (along the positive $y$ axis) with focus at the origin, and with polar axis being the $x$ axis is $ r_1(t) = \dfrac{ 2 p }{ 1 - \sin t } $ where $p$ is ...
Hosam Hajeer's user avatar
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2 votes

Proving that the point is fixed

Let $(O)$ be a circle.Each point $P$(other than $O$) corresponds to a line $p$, called the polar of $P$ with respect to $(O)$, which is perpendicular to $OP$. Conversely, every line $p$ (not passing ...
Stéphane Jaouen's user avatar
2 votes
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Proving that the point is fixed

This was not as easy as I thought. Draw the second tangent (other than $CP$) from $C$ to the circle with centre $O$ and call it $CJ$. Define $E'$ as the intersection of $AB$ and $PJ$. Claim: $E = E'$....
D S's user avatar
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2 votes
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Find Matrix Describing The 2D Ellipse Made by Intersecting a 3D Ellipsoid w/ a Plane

Since the observer is far away, we can assume the observer is at infinity. Therefore what we're looking for is the orthogonal projection of the ellipsoid onto the plane $n^T p = d$ (we can take $d = ...
Hosam Hajeer's user avatar
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2 votes
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Prove that the segment $BE$ intersects the common point of two circles

Let $C \neq X = C_1 \cap C_2$. Note that $$\begin{align} \angle BXC &= 180^\circ -\angle BAC \\ &= 180^\circ -\angle ACB \\ &= 180^\circ - \angle ADB \\ &= \angle BDE \end{align}$$ ...
D S's user avatar
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2 votes

Prove that the segment $BE$ intersects the common point of two circles

Let's mark the point of intersection of two circles as $P$. We know that $DC = DP$, as radiuses of $C_{2}$. Now let $E'$ be the point of intersection of $BP$ and $AD$. We want to prove that $E' = E$. $...
Meison's user avatar
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2 votes
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Proving that the sum of two angles equals to 180°

Let $E$ be the intersection point other than $D$ of the circumcircles of $\triangle DAB$ and $\triangle DMK$. Then $E$ is the spiral similarity center which sends segment $KB$ to $MA$, and since $P$ ...
Kyaw Shin Thant's user avatar
1 vote

How many intersections are there for two confocal parabolas with their axis perpendicular to each other?

There's a simple geometric argument for why it's not 4, but at most 2 points. While intuitively, I can see how it must be exactly 2 and not less, I don't have a clear geometric argument for that yet. ...
Alex K's user avatar
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1 vote

Locus of centers of conics through four points by geometry

OP claims a solution has already been obtained by using a coordinate system, but it is not presented. For clarity, I will derive this here, and show that the midpoints are always on the conic. For ...
DinosaurEgg's user avatar
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1 vote
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Verify the formula for the the 3-simplex

We can argue inductively. If $S = \{\mathbf x \in \mathbb R^4 : \mathbf x \ge 0 \text{ and } x_1+x_2+x_3+x_4=1\}$ is the set we're trying to understand, then it has four faces given by the ...
Misha Lavrov's user avatar

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