0
votes
0answers
16 views

The normalisation map is a bi-Lipschitz map?

Let $X$ a reduced analytic space, $n: W \rightarrow X$ the normalisation map, $W$ the normalisation of $X$ and $S$ the singular set of $X$. When we restrict $n$ to $W\setminus n^{-1}(S)$, we know that ...
1
vote
2answers
40 views

Determine the nature of singularities and calculate the residue of $f(z)=\frac{e^z-\mathrm{sin}z-1}{z^5+z^3}$

$$f(z)=\frac{e^z-\mathrm{sin}z-1}{z^5+z^3},\;\;\;\;\;\;\; \mathrm{Res}[f(z),0]$$ I am having trouble determining the nature of singularities. This is what I managed to do: ...
3
votes
2answers
66 views

Types of singularities of a function

How can I determine the type of a singularity of a function $$f(z)={e^{1/z} \over z-1}+{\pi z \over 2\sin(\pi z)}$$ at $z_0=0$? I don't see an easy way to represent it using Laurent series, neither ...
1
vote
1answer
41 views

Question regarding singularity of a complex function

Consider the function $$f(z) = {1 \over (z-i)(z+i)}$$ with a Laurent series expansion at $z_0=i$ on a domain $\;\Omega=\left\{z\in \mathbb{C}:2\lt\left|z-i\right|\right\}$ $$\begin{eqnarray}f(z)={1 ...
1
vote
1answer
54 views

non-removable singularities of a function are essential singularities of the composition function

Let $f$ be a non-constant enrire function on $\mathbb{C}$ such that $f(z+i)=f(z)$ for all $z$. Let $U$ be an open subset of $C$ and $z_0\in U$. Let $g:U\setminus\{z_0\}\longrightarrow\mathbb{C}$ be ...
0
votes
1answer
23 views

Question about non essential singulariy

When reading Ahlfor's Complex Analysis book, I came across the notion of non essential singularity. I know that for a function $f(z)$ an element $a\in\mathbb C$ is a non essential singularity iff ...
1
vote
1answer
43 views

Singularity Classification

Suppose that I have the following function: $$f(z)=\sin\left(\frac{1}{\sin(\frac{1}{z})}\right)$$ If I'm trying to characterize singularities, I know that singularities will be found whenever ...
2
votes
1answer
98 views

Removable singularities of a holomorphic function

So, I'm a little confused about removable singularities. Consider the function below: $$f(z)=\frac{1}{(1+z^2)^{2/3}}$$ Obviously, we have isolated singularities at the points $z = \pm i$. ...
2
votes
1answer
66 views

Removable singularities for continuous functions

Let $f: D - K \rightarrow \mathbb{C}$ be holomorphic, where $D$ is a planar domain and $K$ is a compact subset of $D$. Suppose that $f$ extends continuously to all of $D$. On which conditions on $K$ ...
1
vote
2answers
50 views

Classifying singularity

Having trouble classifying a singularity... $f(z)=$$z^2-1\over z^6+2z^5+z^4$ with $z_0=0$ and $z_0=-1$ The $z_0=0$ is pretty simple, just need to put $z^4$ in evidence. But $z_0=-1$ I can't seem to ...
1
vote
1answer
36 views

Finding the types of singularities of $f(z)=\frac{1}{z\cdot (e^z -1 )}$

I am getting trouble to find the types of singularities of $$f(z)=\frac{1}{z\cdot (e^z -1 )}$$ What I tried to do is: $z=0$ $z=2\pi k i$ for $z=2\pi k i$ its in order 1, but for the first one I ...
2
votes
1answer
61 views

Laurent series of an analytic function divided by $z$

This is a probably basic question about Laurent series. Say $g(z)$ is an analytic function, that $g(0) = 0$, and $f(z) = g(z)/z$. My textbook says $z = 0$ is a removable singularity of $f(z)$. A ...
1
vote
0answers
63 views

How to analyze the asymptotic properties of this function?

Let the function $$f(\mathbf{r})=\int_{\Omega }e^{i\mathbf{k} \cdot \mathbf{r}}d^2\mathbf{k}$$, where $\mathbf{k} ,\mathbf{r}\in\mathbb{R}^2$, and $\Omega \subset \mathbb{R}^2$ is some finite region ...
1
vote
2answers
146 views

Are the convergence radii circles of a Laurent-series always caused by isolated singularities?

Laurent series $$f(z) := \sum_{n=-\infty}^\infty a_n (z-c)^n$$ converge for $r<|z-c|<R$ where $$r = \limsup_{n\to\infty}|a_{-n}|^{\frac1n}, \\\frac1R = \limsup_{n\to\infty}|a_n|^{\frac1n}.$$ ...
2
votes
1answer
51 views

Growth rate of Taylor convergents near pole

For any fixed $z_0\in\mathbb{C}\setminus \{0\}$ and $\beta\in\mathbb{R}^{+}$, prove that $$\left.T_n\left(\log^{\beta}z;z_0\right)\right|_{z=0}\sim\log^{\beta} n$$ Note: I observed that this holds ...
4
votes
3answers
1k views

Type of singularity of $\log z$ at $z=0$

What type of singularity is $z=0$ for $\log z$ (any branch)? What is the Laurent series for $\log z$ centered at 0, if exist? If the Laurent series has the form $\sum_{k=-\infty}^{\infty} a_kx^k$, ...
3
votes
2answers
338 views

Proving that a function has a removable singularity at infinity

I'm having trouble with the following exercise from Ahlfors' text (not homework) "If $f(z)$ is analytic in a neighborhood of $\infty$ and if $z^{-1} \Re f(z) \to0$ as $z \to \infty$, show that ...
4
votes
2answers
211 views

Singularities of $f(z)=z/\cos(z)$

Regarding complex functions (in complex variables), I was wondering why the function $g(z)= \cos(z)$ has a singularity at $z = \infty$ but $f(z)= \dfrac{z}{\cos(z)}$ does not. I am a bit confused ...
11
votes
1answer
517 views

Is there a classification of isolated essential singularities?

In the thread Why do we categorize all other (iso.) singularities as "essential"?, here is one of the questions that was asked: Do we not care about essential singularities to classify ...
1
vote
1answer
72 views

Removable Singularity with bound on derivative

Here is a question from a practice exam: Suppose $g(z)$ is a holomorphic function everywhere except the origin. Also suppose $$ |g'(z)|\leq \frac{1}{|z|^{3/2}} \quad \text{ for } 0<|z|\leq 1 $$ ...
2
votes
1answer
64 views

Do singularities always appear on all Riemann sheets?

Consider a function $$f(z) = \frac{\ln z}{z^2+1}.$$ Besides the branching point $z=0$, the function also has singularities at $z = \pm i$. This singularities should appear on all Riemann sheets. Is ...
0
votes
1answer
136 views

questions about singularities and complex functions having poles of order k , proofs and examples

1)i need an example of a non isolated singularity 2) also i need an entire function which assumes every complex value but the number 1+2i and i want to know the way in order to solve some other ...
2
votes
2answers
558 views

Contour integral $\int_{|z|=1}\exp(1/z)\sin(1/z)dz$

Evaluate the contour integral $$\int_{|z|=1}\exp(1/z)\sin(1/z)\,dz$$ along the circle $|z|=1$ counterclockwise once. The singularities are $\dfrac1{\pi k},k\in\mathbb{Z}$ plus the limit point $0$. So ...
1
vote
2answers
305 views

Removable singularity and laurent series

How to show $z=\pm\pi$ is a removable singularity for $\frac1{\sin z}+\frac{2z}{z^2-\pi^2}$? I tried to compute the Laurent series, specifically the coefficients for $1/z,1/z^2,...$ since if we can ...
3
votes
1answer
95 views

Does $\frac {z^5}{\sin z^2-z^2}$ have a non-isolated singularity at $0$?

Does $\frac {z^5}{\sin z^2-z^2}$ have a non-isolated singularity at $0$? If so, is it not meaningful to discuss its residue at $0$?
2
votes
2answers
302 views

What is $\lim\limits_{z \to 0} |z \cdot \sin(\frac{1}{z})|$ for $z \in \mathbb C$?

What is $\lim\limits_{z \to 0} |z \cdot \sin(\frac{1}{z})|$ for $z \in \mathbb C^*$? I need it to determine the type of the singularity at $z = 0$.
1
vote
1answer
166 views

Prove that $f(z)$ can not be a polynomial

Suppose $f(z)$ and $g(z)$ are entire functions and that $f(z)$ is not constant. If $|f(z)| < |g(z)|$ for all $z \in \mathbb C, $ prove that $f(z)$ can not be a polynomial. I was thinking what I ...
0
votes
3answers
421 views

Singularity - Removable or Pole?

For the complex-valued function $$f(z) = \left(\frac{\sin 3z}{z^2}-\frac{3}{z}\right)$$ classify the singularity at $z=0$ and calculate its residue. Attempt at Solution Rewriting $f(z) = ...
0
votes
1answer
225 views

Question on the Proof of Casorati Weierstrass

The Casorati Weierstrass Theorem: Let $f:X\subseteq \mathbb{C}\to \mathbb{C}$ have an essential singularity at $w\in \mathbb{C}$. Then, \begin{equation}\forall \epsilon,\delta>0,\zeta\in ...
5
votes
2answers
612 views

Singularities of $e^{z - \frac{1}{z}}$

I believe $e^{z - \frac{1}{z}}$ has essential singularities at $z = 0$ and $z = \infty$ (in both cases because of a $\frac{1}{z}$ in the exponent) but I'm having a hard time proving this. How can one ...