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1answer
35 views

Help to clarify inductive step for proof of $\mathbb{N_m} \rightarrow \mathbb{N}_n\Rightarrow m\le n$

The statement to prove is: If there exists an injection $\mathbb{N_m} \rightarrow \mathbb{N}_n$ then $m\le n$ The solution says to prove by induction on $n$. I just need help on the inductive ...
0
votes
5answers
48 views

Proof of $\forall n \in \Bbb N$, $n > 2 \implies n! < n^n$

What I've got so far is this: Base case: n = 3 then $3 *2 * 1 = 6$ and $3^3 = 27$ $\therefore 6 < 27, 3! < 3^3$ So the base case is true. So if we assume $n! < n^n$ (n > 2) $(n + 1)! = ...
1
vote
4answers
40 views

Prove $\forall n \in\Bbb N$, $0 < a < 1$ $\implies$ $a^n \leq 1$

I'm trying to prove this by induction but I'm running into some trouble. The base case is $0$, so, $a^0 = 1$, the inequality holds true Being new to induction, I don't exactly know what to do for ...
0
votes
3answers
37 views

How do I reduce this induction problem at the k+1 step

Show that $2^n > n^2$ through induction and so far I got to the $k+1$ step, but I am stuck. I have $2^{k+1} = 2 +2^k$, but I don`t know how the book turned it into $k^2 +k^2$. The book then ...
0
votes
2answers
47 views

Proof by induction $\sum_{k=1}^{n}$ $k \binom{n}{k}$ $= n2^{n-1}$ for each natural number n [duplicate]

Prove by induction that $\sum_{k=1}^{n}$ $k \binom{n}{k}$ $= n2^{n-1}$ for each natural number n
1
vote
0answers
57 views

Prove: $a^m\cdot a^n \cdot a^p=a^{m+n+p}$

How can I prove the following: Prop.: let be $m,n,p \in \Bbb{N}$ and $a \in \Bbb{R}$ then $$a^m\cdot a^n \cdot a^p=a^{m+n+p}$$ ??? I thinked by induction and I must prove: 1) $a^0\cdot a^0 \cdot ...
0
votes
2answers
44 views

Prove that $n<(3/2)^n$ for any $n$ with induction [closed]

need help with induction with inequality, I suck at it. $n<\left(\frac{3}{2}\right)^n$ for any $n$
2
votes
1answer
28 views

Question on Induction (Very Simple)

I've just started a course in mathematics at university, and our current topic is mathematical induction. I've been given the following question: $$1+4+4^2+....+4^{n-1}=\frac{4^{n}-1}{3}.$$ I get ...
0
votes
3answers
54 views

In proof by induction, what does it mean when condition for inductive step is lesser than the propsition itself?

My question is regarding the question posed at the end of the proof. My answer is that the result does not hold for all $m \ge 7$ because when $m=7$, the result is $343 \le 128$, which is false. ...
0
votes
1answer
33 views

Base case in the Binet formula (Proof by strong induction)

I don't understand why the author says that the inductive formula does not apply until $u_3$. The formula does not depend on other terms in the Fibonacci sequence, so I thought I could just prove it ...
1
vote
0answers
39 views

Euler proof of the formula for factorial?

Let me be formal and write the formula Euler's Formula: Let a and n by nonnegative integers with $a\geq n.$ Then $$n!=a^n-\binom{n}{1}(a-1)^n+\binom{n}{2}(a-2)^n-\binom{n}{3}(a-3)^n+ ...
1
vote
1answer
50 views

How to prove a very basic algorithm by induction

I just studied proofs by induction on a math book here and everything is neat and funny: the general strategy is to assume the LHS to be true, and use it to prove the RHS (for the inductive step). Now ...
2
votes
2answers
90 views

Proof by induction that $(1^3 + 2^3 + 3^3+\cdots+n^3) = (1 + 2 + \cdots + n)^2$

I'm sitting with the proof in front of me, but I do not understand it. $$A = \{n \in Z^{++} \mid (1^3 + 2^3 + 3^3+\cdots+n^3) = (1 + 2 + \cdots + n)^2\}$$ The first step of proof by induction is ...
1
vote
3answers
62 views

Use induction to prove that $2^n$ divides $(2n)!$ for any $n\in\mathbb{Z}_{\geq0}.$ [duplicate]

Use induction to prove that $2^n$ divides $(2n)!$ for any $n\in\mathbb{Z}_{\geq0}.$ How would you do the inductive step for this proof? I have the base case done.
3
votes
0answers
39 views

Do I need to use induction to have sufficient rigor in this proof?

I'm taking my first analysis class this summer. The professor asked us to prove that $a^{2n}-b^{2n}$ is divisible by $a+b$. After dorking around with the first couple of $n$ I was able to come up ...
2
votes
2answers
36 views

Prove by induction that $\sum_{i=1}^n i!\times i=(n+1)!-1$ for all $n\in \mathbb{N}$

So far I have, If $P(n):\sum_{i=1}^n i!\times i=(n+1)!-1$, then $P(1):\sum_{i=1}^1 i!\times i=1$ and $(1+1)!-1=1$ , so P(1) is true. I know I now have to assume P(K) is true, such that ...
2
votes
3answers
44 views

Strong Induction, assuming k<n where k and n are not numbers

In strong Induction for the induction hypothesis you assume for all K, p(k) for k If for example I am working with trees and not natural numbers can I still use this style of proof? For example if I ...
3
votes
1answer
122 views

Why is this more-detailed proof more acceptable than its trivial counterpart?

Say that we're asked to give a proof of 'proof by induction'. i.e. for some property $P$, proving that $$\forall n,P(1) \wedge [P(k) \implies P(k+1)] \implies \forall n, P(n)$$. Now, I understand ...
1
vote
1answer
18 views

inductive proof of binary existence

Can someone help me witha well exlpained inductive proof of option 2 problem 2. I ha e read many different ones but they dont really make sense to me and I need to know how to do this for my final. ...
1
vote
1answer
271 views

induction proof for kleene star

i am going through some past exam paper questions on regular languages for some revision, and i am having a bit of trouble with converting general ideas into formal mathematical proofs. the question ...
0
votes
1answer
44 views

Prove by Induction that: $1+nx\le (1+x)^n$?

$1+nx\le (1+x)^n$, for all real numbers $x>-1$ and integers $n\ge 2$. Can you please also explain a little of the basic step and the inductions step. Thank you in advance.
2
votes
5answers
104 views

Hint in Proving that $n^2\le n!$

The problem is to find the values of n such $n^2\le n!$. I have found this set to be {${n\in Z^+| n\le1 \lor n\ge 4}$} I've used a proof by cases to prove the first part ($\forall n\le 1$) which was ...
0
votes
2answers
56 views

Proof by induction sum $2^j = 2^{n+1} - 1$

I am trying to solve a previous test for an exam, and there are no solutions. The problem I am trying to solve is If $n$ is a natural number, then $1 + 2 + 2^2 + 2+3 + ... + 2^n = 2^{n+1} -1$ ...
3
votes
0answers
67 views

Cauchy-Euler Equation of order $n$

What I wish to prove is that for a Cauchy-Euler equation of order $n$, the substitution $x=e^{t}$ transforms it into a linear differential equation with constant coefficients. To put it as a theorem: ...
0
votes
1answer
25 views

Proving sequence statement using mathematical induction, $d_n = \frac{2}{n!}$

I'm stuck on this homework problem. I must prove the statement using mathematical induction Given: A sequence $d_1, d_2, d_3, ...$ is defined by letting $d_1 = 2$ and for all integers k $\ge$ 2. $$ ...
6
votes
0answers
67 views

My first proof that uses the well-ordering principle (very simple number theory). Please mark/grade.

What do you think about my first proof that uses the well-ordering principle? Please mark/grade. Theorem The sum of the cubes of three consecutive natural numbers is a multiple of 9. Proof ...
1
vote
4answers
103 views

proof by induction: sum of binomial coefficients

Question: Prove that the sum of the binomial coefficients for the nth power of $(x + y)$ is $2^n$. i.e. the sum of the numbers in the $(n + 1)^{st}$ row of Pascal’s Triangle is $2^n$ i.e. prove ...
2
votes
0answers
48 views

My first proof employing strong induction / complete induction (very simple number theory). Please mark/grade.

What do you think about my first proof employing strong induction? What mark/grade would you give me? Theorem Every natural number greater than 1 is a product of one or more primes. Proof First, ...
17
votes
3answers
710 views

My first induction proof (very simple number theory). Please mark/grade.

What do you think about my first induction proof? Please mark/grade. Theorem The sum of the cubes of three consecutive natural numbers is a multiple of 9. Proof First, introducing a predicate ...
1
vote
0answers
47 views

Proof by induction for all positive integers

$\sum_{j=1}^n j^2 = \frac{n(n+1)(2n + 1)}{6}$ So I did the obvious and plugged one to show that $1^2 = \frac{1(1+1)(2(1) + 1)}{6}$ Now I am trying to show that $1^2 + 2^2 + ... + n^2 + (n + 1)^2 = ...
2
votes
2answers
98 views

show that $2n\choose n$ is divisible by 2 [duplicate]

I tried using induction, but in the inductive step, I get: If $2n\choose n$ is divisible then I want to see that $2n +2\choose n +1$ $${2n +2\choose n +1} = (2n + 2)!/(n+1)!(n +1)! = {2n\choose n} ...
0
votes
0answers
53 views

The Toad and Frog Game - Proof by Inducation

Toads and Frogs is played on a 1 × n strip of squares. At any time, each square is either empty or occupied by a single toad or frog. Although the game may start at any configuration, it is customary ...
1
vote
3answers
49 views

Simple induction proof

Im having a lot of trouble proving by induction that $3^n + 5^n \geq 2^{n+2}.$ The base step is easy, but I don't seem to find the way to proof the inductive step.
2
votes
2answers
79 views

Induction: Show: $\frac{1}{2} \times \frac{3}{4} \times \frac{5}{6} \times … \times \frac{2n-1}{2n} \leq \frac{1}{\sqrt{3n+1}}$

The question: Show by using induction that: $\frac{1}{2} \times \frac{3}{4} \times \frac{5}{6} \times ... \times \frac{2n-1}{2n} \leq \frac{1}{\sqrt{3n+1}}$ for all $n$ $\in$ $Z_+$ My attempt at a ...
4
votes
3answers
92 views

Well-ordering principle on $\mathbb N \iff$ Principle of induction $\iff$ Principle of strong induction: How to prove one of them?

Well-ordering principle on $\mathbb N \iff$ Principle of induction $\iff$ Principle of strong induction How to prove one of them ? On Proofwiki there is an article proving the equivalence of the ...
1
vote
2answers
67 views

What is wrong with the proof given below?

This problem comes from Solow's book, 2nd edition. What is wrong with the proof given below? If $r$ is a real number with $|r| \leq 1$, then for all integers $n \geq 1, 1 + r + r^2 + \ldots + ...
0
votes
2answers
36 views

How to prove statement with two variable by induction

I am trying to prove following statement: $[m,n]$ is a set of functions defined as $f \in [m,n] \leftrightarrow f: \{1,...,m\} \rightarrow \{1,...,n\}$. The size of $[m,n]$ is $n^m$ for $m,n \in ...
1
vote
1answer
85 views

7) Prove that $2n-3 \leq 2^{n-2}$ for all $n \geq 5$ by mathematical induction [duplicate]

Prove that $2n-3\leq 2^{n-2}$ , for all $n \geq 5$ by mathematical induction I have to prove by mathematical induction that: $2n-3\leq 2^{n-2}$ , for all $n \geq 5$
0
votes
2answers
53 views

Prove that $2n-3\leq 2^{n-2}$ , for all $n \geq 5$ by mathematical induction

Prove that $2n-3\leq 2^{n-2}$ , for all $n \geq 5$ by mathematical induction I have to prove by mathematical induction that: $2n-3\leq 2^{n-2}$ , for all $n \geq 5$ Thank you for the Review.
3
votes
2answers
85 views

Is this approach to induction valid?

This is a homework problem: Prove that: $$ 3^{4n+1} + 5^{2n+1}$$ is divisible by $8$ for every natural number $n$. Base case: $$n = 0$$ $$ 3^{0 + 1} + 5^{0 + 1} = 8$$ $$8\bmod8 = 0 $$ Base case ...
1
vote
1answer
80 views

Is this a correct proof by contradiction?

Prove that if a set $A$ of natural numbers contains $n_0$ and contains $k+1$ whenever it contains $k$, then $A$ contains all natural numbers $\geq n_0$. I have attempted a proof by contradiction as ...
1
vote
4answers
233 views

Prove by induction that $10^n -1$ is divisible by 11 for every even natural number

Prove by induction that $10^n -1$ is divisible by 11 for every even natural number n. $0 \notin N$ Base Case: n = 2, since it is the first even natural number. $10^2 -1 = 99$ which is divisible by ...
3
votes
2answers
82 views

Is this how you prove by induction for inequalities?

the question is here: http://cpsc.ualr.edu/srini/DM/chapters/examples/ex2.3.2.html My solution is as below:
0
votes
1answer
52 views

Proof by induction; simplify when adding k+1th term. Understanding induction.

I want to prove: $$(-\frac{1}{2})^0 + (-\frac{1}{2})^1 + \cdots + (-\frac{1}{2})^k + (-\frac{1}{2})^{k+1} = \frac{2^{k+1}+(-1^k)}{3\cdot2^k} + (-\frac{1}{2})^{k+1}$$ How do I simplify the last bit, ...
2
votes
4answers
70 views

Prove that for $n\ge 8$ there are nonnegative integers x and y s.t $3x+5y=n$

Prove that for every integer $n\ge 8$ there are nonnegative integers $x$ and $y$ such that $3x+5y=n$ Attempt: First of all I want to make it clear whether zero is a nonnegative integer. It ...
1
vote
1answer
128 views

Prove by minimum counterexample that $2^n>10n$ for $n>5$

Prove by minimum counterexample that for all integers $n>5$ the statement $2^n>10n$ is true. Attempt: Let $S$ be a set of counterexamples, $S=\{n \in \mathbb{Z_+}: 2^n \le 10n, \space ...
2
votes
1answer
77 views

Use induction on $n$ to prove that $2n+1<2^n$ for all integers $n≥3$.

Use induction on n to prove that $2n+1<2^n$ for all integers $n\geq 3$. My attempt: Let $P(n)$ be the statement $2n+1<2^n$. Base case: Prove that $P(3)$ is true. $LS = 2(3)+1=7$ and ...
3
votes
2answers
95 views

Argument over an induction proof

My friend gave me a problem. Define a sequence $<a_n>$ by the recurrence relation :$$ a_{n+2} - 6a_{n+1} + 8a_n = 0 $$ and $a_1 = 4, a_2 = 8 $. Find the general term $a_n$ in closed form. ...
2
votes
1answer
77 views

Inductive hypothesis vs induction hypothesis

I'm doing a proof by induction. Should I refer to induction hypothesis or to inductive hypothesis in the proof?
1
vote
2answers
52 views

Help with a basic induction proof

The theorem given is: 'If n is a natural number then n can be written in the form 2a + 3b for some integers a and b.' How would I prove this by induction? I've had a go at proving this but I don't ...