Operator theory is the branch of functional analysis that focuses on bounded linear operators, but it includes closed operators and nonlinear operators. Operator theory is also concerned with the study of algebras of operators.

learn more… | top users | synonyms

0
votes
1answer
18 views

Unitary element in a C*-algebra

Suppose $\Bbb T$ is the unit circle and $M$ is the C*-algebra of all $2\times 2$ complex matrices. Consider the C*-algebra $A: = C(\Bbb T, M)$. Let $E$ and $F$ be the projections in $A$ given by ...
1
vote
1answer
27 views

Are symmetric matrices necessarily positive-definite / positive semi-definite?

I am trying to prove this just to be clear about this but I don't have enough conditions to force this idea to be true, so I doubt it is. Are symmetric matrices always at least positive ...
-2
votes
1answer
49 views

Some question about linear operator on normed space [on hold]

$1)$ let $X$ and $Y$ be normed space , show that a linear operator $T:X\rightarrow Y$ is bounded if and only if $T$ maps bounded sets in $X$ into bounded sets in $Y$ $2)$show that the operator ...
0
votes
0answers
14 views

Singular Spectrum: Techniques?

Given a Hilbert space $\mathcal{H}$. Let the Lebesgue measure be $\lambda$. Consider a Hamiltonian: $$H:\mathcal{D}(H)\to\mathcal{H}:\quad H=H^*$$ Denote its spectral measure by: ...
2
votes
1answer
34 views

If I want to prove that $M^{\perp}$is a closed

If I want to prove that $M^{\perp}$is a closed Can I say because it is the inverse image of $0$ by continuos function ( projection operator )
2
votes
1answer
29 views

find $\lambda$ such that the integral has a solution.

I have the integral equation: $u(x) = f(x) + \lambda \int_0^{\frac{1}{2}}u(y)dy$ I have to find $\lambda$ such that the integral has a solution. How to approach such problems?
1
vote
0answers
14 views

Is the Hankel Transform a Hankel Operator

The "Hankel Transform" is the infinite weighted sum of the Bessel function. At the top of the wikipedia article http://en.wikipedia.org/wiki/Hankel_transform it says Not to be confused with the ...
0
votes
0answers
23 views

Lummer-Phillips theorem for generator of strongly continuous semigroup

Let $L^{2}([a,b];\mathbb{K}^{n})$ be the standard Lebesgue space with its standard inner product. Consider the operator $A$ defined by $\displaystyle ...
2
votes
1answer
35 views

Show that $C(S^n)$ is the universal $C^*$-Algebra of selfadjoint, commutative $x_0,\ldots,x_n$ with $\sum x_i^2 = 1$

Let $x_0,\ldots,x_n$ be symbols with relations $x_i=x_i^*$, $x_i x_j = x_j x_i$ and $\sum_i x_i^2 = 1$. Then I want to show that the universal $C^*$-Algebra $A$ of these relations exists and that ...
1
vote
1answer
21 views

check if a linear operator is bounded

show that $Tf = f(0)$ is not a bounded linear functional on the space of continuous functions measured with the L2 norm, but it is a bounded linear functional if measured using the uniform norm. ...
0
votes
0answers
12 views

How are $C(S^1)$ and the crossed product algebra $C(\mathbb{R})\ltimes \mathbb{Z}$ Morita equivalent?

In Connes' Noncommutative geometry one construct "noncommutative quotients" by taking certain crossproduct algebra's. Given a group $G$ acting on a set $X$ through an action $\alpha$ we can form the ...
1
vote
1answer
41 views

Given a singular matrix, I am tring to find an invertible matrix… (Finite Dimensional Space)

In coordinates and in a finite-dimensional space, how would I prove that given any singular $n$x$n$ matrix $A$, any $\epsilon\gt0$ and any matrix norm $||.||$, there is an invertible $n$x$n$ matrix ...
2
votes
0answers
39 views

Hamiltonian: Commutator (II)

Problem Given a Hilbert space $\mathcal{H}$. Consider a Hamiltonian: $$H:\mathcal{D}(H)\to\mathcal{H}:\quad H=H^*$$ and an operator: $$A:\mathcal{D}(A)\to\mathcal{H}:\quad A=A^*$$ Denote for ...
0
votes
1answer
34 views

A continuous field of C* algebra, $C(\mathbb T)\rtimes\mathbb Z_2$

Given a $C^*$-algebra, $A=${$f:[0,1]\rightarrow M_2(\mathbb C)$ where $f(0),f(1) $ are diagonal } which is isomorphic to $C(\mathbb T)\rtimes\mathbb Z_2$, How can I determine its continuous field ...
0
votes
0answers
4 views

Eigenvalue spectrum of backward Fokker-Planck operator

I encountered a paper in physics, in which the author states that an operator of the following form (backward Fokker-Planck) $\Lambda = P(x)\frac{d}{dx}+Q\frac{d^2}{dx^2}$ has an eigenvalue 0 and ...
1
vote
1answer
21 views

Convergence in strong operator topology and norm topology

Let $(T_n)\subset B(H)$ be a sequence of operators such that $T_n\to 0$ in strong operator topology. Show that $\|T_nK\|\to 0$ and $\|KT_n\|\to 0$ for every compact operator $K$. Let $f,g \neq 0 ...
1
vote
2answers
17 views

Show that $ T \notin X' $ if $ X = C([0,1]) $ is equipped with the norm $ \| f \|_{L^{2}} \stackrel{\text{df}}{=} \sqrt{\int_{0}^{1} |f|^{2}} $.

Let $ T $ be an operator on $ X = C([0,1]) $ defined by $ T(f) \stackrel{\text{df}}{=} f(0) $. I want to show that $ T \notin X' $ (the dual space of $ X $) if $ X $ is equipped with the norm $$ \| f ...
1
vote
1answer
38 views

Closed unit ball of positive bounded operator space and its extreme point

Let $H$ be infinite dimensional Hilbert space. Then the closed unit ball of positive bounded operator space $B(H)^+$ is not the convex hull of the projections of $B(H)$. Please help me. Thanks.
7
votes
2answers
102 views

The spectrum of a self-adjoint operator on $\mathcal l^2$

Let $S$ be the unilateral shift operator on $\mathcal l^2$ (which shifts one place to the right) and $S^*$ its adjoint, the backward shift (which shifts one place to the left). I've been trying to ...
1
vote
1answer
13 views

$\max$ Operator on a Sum of Integrals

Define the value function $$v(k) := \max_c\left[\int_0^t{F(s,c,k)ds}+\int_t^\infty{F(s,c,k)ds}\right]$$ Is this expression equal to $$v(k) := ...
1
vote
0answers
10 views

Linear operator differentiation on a torus

I'm trying to analyze this article about area-preserving diffeomorphisms and don't quite understand a sentence. 4.1. Linear involutions. We start characterizing the linear involutions $R \! : ...
0
votes
1answer
12 views

An extension of a corollary to Fuglede's theorem

Fuglede's theorem states that if $T,N\in B(H)$ for some Hilbert space $H$ and $N$ is normal and $TN = NT$, then $TN^* = N^*T$. A corollary to this theorem is that if $M,N \in B(H)$ are normal and ...
1
vote
0answers
23 views

Hamiltonian: Commutator

Given a Hilbert space $\mathcal{H}$. Consider a Hamiltonian: $$H:\mathcal{D}(H)\to\mathcal{H}:\quad H=H^*$$ and an operator: $$A:\mathcal{D}(A)\to\mathcal{H}:\quad A=A^*$$ Denote for shorthand: ...
0
votes
3answers
46 views

Selfadjoint Operators: Sesquilinear Form (II)

Given a Hilbert space $\mathcal{H}$. Consider a positive form: $$s:\mathcal{D}\to\mathcal{H}:\quad s(\varphi,\varphi)\geq0$$ Introduce its form space: ...
2
votes
1answer
26 views

Integral Operator Contraction

I have the following question: I've found the bound as follows $\lvert T f(x)\rvert \le C\lVert f \rVert(x-a)$ using the fact that K is bounded on the closed square so we have $max \lvert K(x,y) ...
0
votes
1answer
28 views

Invariance of semigroups

$A$ is the infinitesimal generator of the $C_{0}$-semigroup $(T(t))_{t\ge 0}$ and $V$ is a one dimensional linear subspace of $X$. I want to show that $V$ is $T(t)$-invariant $\iff$ ...
0
votes
1answer
27 views

Selfadjoint Operators: Sesquilinear Form (I)

Given a Hilbert space $\mathcal{H}$. Consider a dense positive form: $$s:\mathcal{D}\times\mathcal{D}\to\mathbb{C}:\quad s(\varphi,\varphi)\geq0\quad(\overline{\mathcal{D}}=\mathcal{H})$$ Construct ...
1
vote
1answer
36 views

Introducing an operator by a bilinear form

Let $I = (0, 1)$ and $H_0^2 (I)$ the closure of $C_c^\infty (I)$ in $W^{2, 2} (I)$. Consider $$a : H_0^2 (I) \times H_0^2 (I) \to \mathbb{R}$$ defined by $$a(u, v) = \int\limits_I u''(x) v''(x) \, ...
2
votes
1answer
41 views

Spectrum of operator $Af(t) = \int_0^{t^2} f(s)ds$ on $L^2[0,1]$

Consider a linear operator $A\colon L^2[0,1]\rightarrow L^2[0,1]$ that acts as follows: $$Af(t) = \int_0^{t^2} f(s)ds$$ The problem is to compute its spectrum. I know that the operator is compact ...
2
votes
2answers
36 views

Are elements of a $C^*$-Algebra strictly positive iff their spectrum is strictly positive?

Let $A$ be a $C^*$-Algebra. An element $a\in A$ is said to be positive iff $a=a^*$ and the spectrum $\sigma(a)$ is nonnegative, ie. $\sigma(a)\subset[0,\infty)$. This is equivalent to $\varphi(a)\ge ...
1
vote
1answer
23 views

Congruence Property of Monotone Operators

A map $T$ is called strictly monotone if for $x\ne y$, $\langle u-v,x-y\rangle>0$ for all $u\in T(x),v\in T(y)$. Let $A$ be an $m\times n$ matrix and $b\in\mathbb R^m$. I want to prove that if ...
1
vote
0answers
23 views

weak closure of unitary group in $B(H)$

Let $H$ be a Hilbert space with dim $H=\infty$ , and $\cal{U}$ be the group of all unitaries on $H$. Show that the weak closure of $\cal{U}$ is a semigroup with respect to the multiplication. I know ...
2
votes
0answers
38 views

(soft question) why do we study complex measures and complex-valued functionals in modern analysis

Recently I am struggling with "complex" things for my "real" analysis class. We are using Folland's Real analysis, 2nd for text book. It seems that Folland is trying to use complex-valued functions ...
1
vote
1answer
25 views

Proving strong stability of semigroup

$X$ is the Hilbert space $L^{2}(0,\infty)$ and let $T(t):X\to X$ with $t\ge 0$ be defined by $(T(t)f)(\zeta):=f(t+\zeta)$. I want to prove that the $C_{0}$-semigroup $(T(t))_{t\ge 0}$ is strongly ...
1
vote
0answers
34 views

Bounding the operator

If $X$ is the Hilbert space $L^2(0,\infty)$ equipped with the inner product $$\langle f,g\rangle :=\int_0^\infty f(\zeta)\overline{g(\zeta)}(e^{-\zeta}+1) \, d\zeta,$$ and the operator $T(t):X\to ...
1
vote
1answer
88 views

Generating a contraction semigroup on an energy space

Consider the system of partial differential equations $\displaystyle\frac{\partial Q}{\partial t}(\zeta, t)=-\frac{\partial}{\partial\zeta}\frac{\phi(\zeta, t)}{L(\zeta)}$ ...
2
votes
0answers
21 views

Schrodinger Operator with Finite Discrete Spectrum in $(-\infty, -1]$

I'm reading parts of Reed and Simon's Analysis of Operators and have come across a statement I find puzzling. They say that if $V$ is a bounded function of compact support on $\mathbb{R}^3$ then ...
2
votes
1answer
31 views

closed graph theory and unbounded operator

I am studying unbounded operators and the graphs of those operators. I found that the closure of a graph may not be the graph of any operator. Can someone provide an example of an operator and a ...
2
votes
0answers
24 views

Primitive ideal space of C*(Z2*Z2)

Find the primitive ideal space, the center, a continuous field of $C^*(Z_2*Z_2)$. Here, $C^*(Z_2*Z_2)$ is the full group $C^*$-algebra. I know the definitions of all of them, but I'm having hard ...
1
vote
1answer
16 views

Numerical range of inverse operator

Let $T$ be a bounded self-adjoint operator such that the numerical range is contained in $[a,b]$ with $0<a<b< \infty.$ Does it then follow that the numerical range of $T^{-1}$ is contained in ...
0
votes
0answers
24 views

Using Bounded Operator sequence Theorem

Let E$\subset L_1$ be a set of fourier series functions $e_n(t)=e^{int}$ for $n \in Z$. What is meant by saying to prove $Ge_n$ is a scalar multiple of $e_n$ and it is continuous? How can we prove it? ...
0
votes
0answers
7 views

Composition with a projection remain surjective in a neighborhood of the parameter

Let $H$ be an Hilbert space and $\varphi:H\to \mathbb R^m$ a smooth map. It is known that the map $u\mapsto d_u\varphi$ is continuous from $H$ to the space of linear operators $L(H,\mathbb R^m)$. ...
1
vote
0answers
41 views

Explicit inverse of $\lambda-U$ when $U$ is unitary and $|\lambda|<1$

Let $U$ be a unitary operator on a Hilbert space $\mathcal{H}$. By the spectral theorem, it is known that $\sigma(U)\subseteq \{z\in \mathbb{C}:|z|=1\}$. How can the explicit inverse of $\lambda-U$ be ...
1
vote
2answers
49 views

Universal properties of certain crossed products

So I was wondering if there are any nice universal properties that the crossed product $C^*$ algebra, $C(\mathbb{T})\times_\alpha \mathbb{Z}_2$ satisfies, where $\alpha$ is the action of conjugation. ...
0
votes
0answers
10 views

Normal Operators: Backtransform

Problem Given a Hilbert space $\mathcal{H}$. Consider a normal operator: $$N:\mathcal{D}(T)\to\mathcal{H}:\quad N^*N=NN^*$$ Construct the operator: $$W:=(1+N^*N)^{-1}:\quad Z:=N\sqrt{W}$$ By a ...
1
vote
1answer
37 views

Bounded Operator Norm: Special Element

Given a Banach spaces $X$ and $Y$. Consider a bounded operator: $$T:X\to Y:\quad\|T\|<\infty$$ Then theres an element: $$\|Tx\|=\|T\|\cdot\|x\|\quad(x\neq0)$$ Does it always exist?
1
vote
0answers
33 views

Reducing subspaces of a normal operator

If $A$ is a normal operator on an infinite dimensional Hilbert space $H$, then $H$ is the direct sum of a countably infinite collection of subspaces that reduce $A$, all with the same infinite ...
1
vote
1answer
44 views

Is the space of bounded linear operators from E (space with an inner product) to C (complex numbers) a Hilbert space?

In other words is there an inner product that produces the operator norm? Let $E$ be a space with an inner product. Show that its topological dual $E^*$ equiped with the operator norm is a Hilbert ...
2
votes
1answer
31 views

Norm of integral operator in $L^1(0,2)$

How exactly do I show that an integral operator is bounded. For example, consider the following operator $$ T: L^1(0,2) \to L^1(0,2)\\ (Tf)(x):=\int_0^x tf(t) dt$$ My first approach \begin{align} ...
1
vote
1answer
28 views

Normal Operators: Transform

Given a Hilbert space $\mathcal{H}$. Consider a normal operator: $$N:\mathcal{D}(T)\to\mathcal{H}:\quad N^*N=NN^*$$ Construct the operator: $$W:=(1+N^*N)^{-1}:\quad Z:=N\sqrt{W}$$ Then it is ...