For questions related to the Lambert-W or product log function. This is the inverse function of $f(z) = ze^z$.

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Lambert function approximation $W_0$ branch

I am looking for a simple, inexpensive and very accurate approximation of the Lambert function ($W_0$ branch) ($-1/e < x < 0$).
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1answer
44 views

Does $i = -\frac{(2\;W({\pi\over2}))}{\pi}$

Let $x = -\frac{(2\;W({\pi\over2}))}{\pi}$, where $W$ denotes the Lambert W-function. As $${\log(i^2)\over i} = \pi$$ and $${\log(x^2)\over x}=\pi$$ Does $x = i$?
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1answer
50 views

what is exactly analytic continuation of the product log function

When I solve in wolfram equation like this $xe^x=z$ they give me the solution $x=W_n(z)$ I know about $x=W_0(z) $ and $x=W_{1}(z)$ but for $n$ I searched in the internet but I didn't find anything ...
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1answer
46 views

Question about Lambert W function

I'm looking for a series for $W_0(x)$ for x $\in [\frac{-1}{e},\infty [$ but every time i found only for $x\in [\frac{-1}{e}, \frac{1}{e}]$ and what about a series for $W_-1(x)$ if it is no series ...
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1answer
25 views

solve non linear differential equation: $y'\cdot\alpha+y+\beta\cdot e^{\delta\cdot y}+\theta = 0$

Could somebody help me to solve the non linear differential equation, where $y$ is a function of the time and starts with $y(0)=0$ $$ y'\cdot\alpha+y+\beta\cdot e^{\delta\cdot y}+\theta = 0 $$ It will ...
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1answer
55 views

An aproximation of the lambertw function for a complex number

Here is my problem, I used the fact that $W(x)=\ln(x)-\ln(W(x))$, replacing $W(x)$ by $\ln(x)-\ln(... $ a lot amount of times and it seems to works for simple $x$ but when I try with, for example, ...
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1answer
92 views

Does $\int_0^{\infty} \left( p + q W \left( r e^{- s x + t} \right) + u x \right) e^{- x} d x$ have a closed-form expression?

Does $\int_0^{\infty} \left( p + q W \left( r e^{- s x + t} \right) + u x \right) e^{- x} d x$ (with 6 variables) where W is the Lambert W function (also known as ProductLog in Mathematica) have a ...
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1answer
145 views

Evaluation of an integral involving the Lambert W function

Wikipedia claims that $$\int_0^\infty W\left(\frac{1}{x^2}\right) \,\text dx=\sqrt{2\pi}$$ and a numerical computation seems to confirm this. How can this result be proven?