Tagged Questions
4
votes
1answer
30 views
Trying to understand Theorem 2.27 in a recent paper on the Chebyshev function
In February 2013, Sadegh Nazardonyavi and Semyon Yakubovich posted on arxiv: Sharper estimates for Chebyshev's functions $\vartheta$ and $\psi$.
I have a question about Theorem 2.27 on page 22.
My ...
2
votes
1answer
47 views
Prove that $n^2 \leq \frac{c^n+c^{-n}-2}{c+c^{-1}-2}$.
Let $c \not= 1$ be a real positive number, and let $n$ be a positive integer.
Prove that $$n^2 \leq \frac{c^n+c^{-n}-2}{c+c^{-1}-2}.$$
My initial thought was to try and induct on $n$, but the ...
1
vote
1answer
64 views
Solution to a functional equation
Let $n,i$ be positive integers and $C$ a strictly positive real value.
Consider the equation for $f$ :
$$1*\ln(f(n)) = C * \sum_{3<i* \ln(i) < \sqrt{n}} \left(\ln[f( i* \ln(i) )-1)] - \ln[(f( i* ...
0
votes
0answers
58 views
Using Stirling's Formula to approximate a difference of logarithms of factorials in the same way as Jitsuro Nagura.
In Jitsuro Nagura's classic proof of a prime existing between $x$ and $\frac{6x}{5}$, he uses Stirling's formula to show that:
$$T\left(x\right) - T\left(\frac{x}{2}\right) - ...
0
votes
0answers
42 views
Do these inequalities regarding the gamma function and factorials work?
I am seeing if it is possible to generalize lemma 1 in Nagura's proof that there is always a prime between $x$ and $\frac{6x}{5}$.
In a previous question, I asked whether the following inequality is ...
2
votes
0answers
55 views
Trying to generalize an inequality from Jitsuro Nagura: Does this work?
I am investigating the generality of Lemma 1 in Nagura's proof that there is always a prime between $x$ and $\frac{6x}{5}$.
In Lemma 1, Nagura establishes when $n > 1$, $x \ge 1$:
...
0
votes
0answers
54 views
Inequality with natural numbers.
Let $d_1 \geq d_2 \geq \dots \geq d_n$, $n\geq 3 $ natural numbers.
Prove that
$$ \prod_{i=1}^n(d_i + 1 ) \leq \binom{ \sum_{i=1}^n d_i -d_n +n +2 }{n} - \sum_{j=1}^n \binom{ (\sum_{i=1}^n d_i) - d_j ...
5
votes
1answer
98 views
Understanding a famous proof by Jitsuro Nagura: Need help understanding one step in the main theorem
I am going through the proof by Jitsuro Nagura which shows that there is always a prime between $x$ and $\frac{6x}{5}$ where $x \ge 25$.
Nagura uses the following definitions:
$$\vartheta(x) = ...
1
vote
0answers
26 views
conversion from psi function to prime counting function
Can we convert $\psi(x)$ to $\pi(x)$ without using integrals. Also if $\psi(x)>\psi(y)$
when we can say that $\pi(x)>\pi(y)$ . It seems that $\theta(x)>\theta(y)$ so $\pi(x)>\pi(y)$
but ...
8
votes
1answer
205 views
Is it possible to generalize Ramanujan's lower bound for factorials that he used in his proof of Bertrand's Postulate?
I am starting to feel more confident in my understanding of Ramanujan's proof of Bertrand's postulate. I hope that I am not getting overconfident.
In particular, Ramanujan's does the following ...
2
votes
1answer
46 views
Calculate or bound infimum
Let $a_1, \ldots, a_n \in\mathbb R$ and nonnegative let $b\geq1$ and $c\in [0,1]$.
Calculate or bound from above
$$
\inf \left\{d>0: \sum_{i=1}^n \ln ...
6
votes
1answer
71 views
How to prove $\sum_{i=1}^{n-1}\frac{1}{\operatorname{lcm}(a_i,a_{i+1})}\lt1$ where $a_i\in\mathbb N$ and $a_i\lt a_{i+1}$?
Let $a_1,a_2,\ldots ,a_n\in\mathbb N$ and $a_1\lt a_2\lt\cdots\lt a_n$. Then how to prove $$\sum_{i=1}^{n-1}\frac{1}{\operatorname{lcm}(a_i,a_{i+1})}\lt1$$
Thanks in advance
2
votes
0answers
34 views
Lower bound on diophantine system of inequalities with all but one non-linear constraint
I have a system of $n+1$ diophantine inequalities, in the following form:
$$f_{1}(x_1, x_2, \dots, x_n) \geq 0$$
$$f_{2}(x_1, x_2, \dots, x_n) \geq 0$$
$$\vdots$$
$$f_{m}(x_1, x_2, \dots, x_n) ...
2
votes
0answers
38 views
Primes of the form $\dfrac{n^2-n+4}{2}$ satisfy Hardy-Littlewood analogue?
Let $n,a,b$ be positive integers with $a<b$. Consider primes of the form $f(n)=\dfrac{n^2-n+4}{2}$. Let $C(a,b)$ denote the amount of primes of the form $f(n)$ between (and including) $f(a)$ and ...
5
votes
1answer
163 views
$x^2+y^2=z^2(1+xy)$ prove $z=\min \{x;y;z\}$ (with $x,y,z \in \mathbb{Z^+}$)
$x,y,z \in \mathbb{Z^+}$ such that $x^2+y^2=z^2(1+xy)$. Prove $z=\min \{x;y;z\}$
$$x^2+y^2=z^2(1+xy) \iff xy = \frac{x^2+y^2} {z^2} - 1$$. Assum $z>y \implies xy < x^2/z^2$, we have $xy \in Z ...
1
vote
3answers
45 views
inequality with one number and a sum of numbers
Let $x_1, \ldots, x_n $ be non-zero real number, such that $\sqrt{x_1^2 + \cdots + x_n^2}=1$. Show that for any $i = 1, \ldots, n$,
$$|x_i| \leq \sqrt{\frac{x_1^2 + \cdots + x_n^2}{n}}= ...
1
vote
2answers
102 views
Two Problem: find max, min; number theory: find x, y
Find $x, y \in \mathbb{N}$ such that $$\left.\frac{x^2+y^2}{x-y}~\right|~ 2010$$
Find max and min of $\sqrt{x+1}+\sqrt{5-4x}$ (I know $\max = \frac{3\sqrt{5}}2,\, \min = \frac 3 2$)
4
votes
4answers
137 views
Floor function inequality
I am racking my brain trying to get this problem solved and I can't seem to break it...
Let $m, n$ be positive integers, with $m > 1$. Prove
...
1
vote
3answers
102 views
bound for the product of numbers
Let $n \in N$. Fix $m \in [-n,n]$. I am curious, how to bound from above the following expression
$$
(n-m)^{\frac{n-m}{2}+1}(n+m)^{\frac{n+m+1}{2}}\leq \quad ?
$$
Thank you.
11
votes
2answers
234 views
Find the number of pairs $(m, n)$ of positive integers such that $\frac{ m}{n+1} < \sqrt{2} < \frac{m+1}{n}$
Find the number of pairs $(m, n)$ of positive integers such that $\frac{ m}{n+1} < \sqrt{2} < \frac{m+1}{n}$ Constraint: $m$ and $n$ are both less than or equal to 1000
I toiled over this ...
4
votes
1answer
70 views
inequality with numbers--when its true?
Help me please to understand when the inequality true.
Let $n<N,$ where $n, N$ are natural numbers.
For which $n$ and $N$ the following is true
$$
n^{2n+1}\leq N^{N+1}?
$$
Thank you.
0
votes
0answers
63 views
When inequality for binomial coefficients is true?
I've asked similar question here Inequality for binomial coefficients, but with slightly different assumptions. I am curious what happend if $m, k$ are fixed.
Let $m \leq n, n \leq N$ and $0\leq k ...
1
vote
1answer
115 views
Inequality for binomial coefficients
Let $m \leq n, n \leq N$ and $0\leq k \leq m$.
I am wondering what is the dependence of $n$ and $N$ that for all $m, k$
$$
\frac{{N-m \choose n-k}}{{N \choose n}}\leq 1.
$$
Thank you for your help.
3
votes
2answers
203 views
Bounding the prime counting function
How can I get inequalities that bound the prime counting function if I have the following inequalities for some functions $f(x)$ and $g(x)$: $$ g(x)<\psi(x)<f(x), $$ where $\psi(x)$ is second ...
1
vote
1answer
28 views
Condition when inequality with numbers is true
Let $n\geq 1, m>1, k\leq n$.
I am trying to find condition on $m,$ that
$$
4\sqrt{\pi}(2m)^{mn}\leq2^k
$$
Thank you.
0
votes
1answer
81 views
Prime counting inequality
What is the largest constant $c$, such that
$$ (c)x/\ln(x) < \pi(x)$$ For all integers $n$, also, if no one knows, do you think expecting an anwser is unreasonble?
0
votes
0answers
78 views
Proving a simple inequality
Can someone show that the inequality bellow holds?
$$ f(n) \leq f(n+1) \ $$
Where
$$ \frac{\sum\limits_{k=1}^n \Lambda(k) {k}/{n}\lceil{n}/{k}\rceil{}\{ n/k \}}{\sum\limits_{k=1}^n \Lambda(k)}=f(n)$$
...
1
vote
0answers
50 views
Inequality help
Can someone help me prove the inequality,
$$ \frac{\sum\limits_{k=1}^n \Lambda(k) \frac{k}{n}\lceil\frac{n}{k}\rceil\{ \frac{n}{k} \}}{\sum\limits_{k=1}^n \Lambda(k)}<\ \frac{\sum\limits_{k=1}^n ...
6
votes
0answers
121 views
Question about an upper bound
Let each of the positive integers $a_1 ,\dots, a_n$ be less than $m$ such that the least common multiple of any two of the positive integers $a_1 ,\dots, a_n$ is greater than the integer $m$.
Then ...
1
vote
1answer
50 views
Inequality with numbers
It seems its a simple question, but I am confused.
Let a be natural number and let b be some number $1\le b\le a$.
Find an upper bound for
$$
\frac{a^2+2b^2-4ab-a}{a(a-1)}.
$$
I've got
$$
...
0
votes
3answers
86 views
Properties of Mediants
If $\frac{a}{c} > \frac{b}{d}$, then the mediant of these two fractions is defined as $\frac{a+b}{c+d}$ and can be shown to lie striclty between the two fractions.
My question is can you prove ...
1
vote
3answers
208 views
Generalizing Bernoulli's inequality
We are already familiar with Bernoulli's inequality: $(1+px)\le(1+x)^p$ for $x\ge-1, p\ge1$.
Can this be generalized to say something useful about $(1+p_1x_1+\cdots+p_nx_n)$? For instance, one would ...
1
vote
0answers
35 views
Minimal modulus for the finite field NTT
I need your support.
Suppose I am performing an NTT in a finite field $GF(p)$. I assume it contains the needed primitive root of unity.
I am using it to compute the convolution of two vectors of ...
2
votes
1answer
97 views
inequality proof of $x^{y-1} \ge xy$
How to prove $x^{y-1}\geq xy$ with
$x,y\in \mathbb{R}$ with $x,y\geq 3$ . Do I need induction? Or is there an elegant way?
-2
votes
2answers
142 views
Simple ceiling function problem [closed]
Prove that $\lceil4n/3\rceil\le 4\lceil n/3\rceil$ for all integers $n$. Try to generalize this result to something where something other than 4 and 3 are used.
0
votes
3answers
845 views
Proof by induction of summation inequality
Prove by induction the summation of $\frac1{2^n}$ is greater than or equal to $1+\frac{n}2$.
We start with $$1+\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+\dots+\frac1{2^n}\ge 1+\frac{n}2$$ for all positive ...
0
votes
1answer
120 views
question about psi function in paper on primes
This question is from Nagura's 1952 paper on primes in short intervals. He uses $\psi(x) = \sum_{m=1}^{\infty}\phi(\sqrt[m]{x})$, in which $\phi(x) = \sum_{ p \leq x }\ln p$. Using close arguments ...
12
votes
1answer
246 views
Chebyshev: Proof $\prod \limits_{p \leq 2k}{\;} p > 2^k$
How do I prove the following:
$$\prod_{p \leq 2k} \; p > 2^k \text{ with } p \in \mathbb{P}$$
I tried induction, but I didn't know how to go on because I don't have a look at all numbers.
...
1
vote
2answers
183 views
Proof $\binom{2\phi(r)}{\phi(r)+1} \geq 2^{\phi(r)}$
I try to proof the following
$$\binom{2\phi(r)}{\phi(r)+1} \geq 2^{\phi(r)}$$
with $r \geq 3$ and $r \in \mathbb{P}$. Do I have to make in induction over $r$ or any better ideas?
Any help is ...
6
votes
1answer
194 views
Sum of divisor ratio inequality
Consider the divisors of $n$, $$d_1 = 1, d_2, d_3, ..., d_r=n$$ in ascending order and $r \equiv r(n)$ is the number of divisors of $n$.
Is there any expression $f(n) < r(n)$ such that,
...
2
votes
1answer
333 views
Proof of Chebyshev's theorem
(a) Show that $\int_2^x\frac{\pi(t)}{t^2}dt=\sum_{p\leq x }\frac{1}{p}+o(1)\sim\log\log x.$
(b) Let $\rho(x)$ be the ratio of the two functions involved in the prime number theorem:
...
6
votes
6answers
2k views
Is a prime factor of a number always less than its square root?
I was going through the fundamental theorem in Number Theory where any non zero integer n can be represented as a product of distinct primes. A related problem with this theorem is to prove that for ...
2
votes
2answers
358 views
Non-negative integral solutions of $X_1+X_2+X_3+X_4<n$
The number of non-negative integral solutions of $X_1+X_2+X_3+X_4<n$ (where $n$ is a positive integer) is?
8
votes
2answers
284 views
$ \sum\limits_{i=1}^{p-1} \Bigl( \Bigl\lfloor{\frac{2i^{2}}{p}\Bigr\rfloor}-2\Bigl\lfloor{\frac{i^{2}}{p}\Bigr\rfloor}\Bigr)= \frac{p-1}{2}$
I was working out some problems. This is giving me trouble.
If $p$ is a prime number of the form $4n+1$ then how do i show that:
$$ \sum\limits_{i=1}^{p-1} \Biggl( ...
1
vote
1answer
190 views
Showing that $|\sqrt{3} - m/n| \geq 1/(5n^2)$
Can you help me to prove this inequality
\begin{aligned}
|\sqrt{3} - m/n| \geq 1/(5n^2)
\end{aligned}
where m and n are integers.
Hint:$sqrt(3)$ is irrational.


