Tagged Questions

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Function relating Euler's constant and the golden ratio

Okay, I was messing around on Excel with some coefficients and I stumbled onto this. Not sure if it converges but it gets pretty damn close around the 1024th term mark. Was wondering if somebody could ...
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Help with a proof I can't quite

Let $(F_j)^\infty_{j=1}$ be the sequence of Fibonacci numbers. For all $n \in \mathbb{N}$, $\sum\limits_{k=1}^{2n-1}F_kF_{k+1}=(F_{2n})^2$. I handled the base case quite well but couldn't go very ...
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Factoring for Strong Induction for Fibonacci Sequence

Fibonacci: prove the following theorem: define the Fibonacci sequence $\left\{ a_n\right\}_{n=0}^{\infty}$ by $a_0=a_1=1$ and for integers $k>1$, $a_k=a_{k-1}+a_{k-2}$. Then, for each integer $n$, ...
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Fibonacci Sequence, Golden Ratio

I've been asked to show that $x_n \rightarrow L$ as $n \rightarrow \infty$ where $x_n = F_{n+1}/F_{n}$ for $n \in \mathbb{Z}^+$, where $F_n$ denotes the $n^{th}$ Fibonacci number. I am supposed to use ...
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Fibonacci trick and proving it. [duplicate]

I am trying to learn Fibonacci tricks and I have one that I can not prove. I know it works because Ive tried it multiple times but I have not a clue how to prove. Here it is: ...
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Fibonacci Proof with Induction [duplicate]

$$f(n) = \left\{\begin{matrix} 0 & n=1\\ 1 & n=2\\ f_{n-1} + f_{n-2} & n\geqslant 2\end{matrix}\right.$$ How can I prove by induction that $$f_{n} \geq \left ( 1.5 \right )^{n-1}$$ ...
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Induction on the Fibonacci sequence?

Prove by induction that the $i$th Fibonacci number satisfies the equality: $$F_i = \frac {\phi^i - \hat\phi{}^i}{\sqrt5}$$ where $\phi$ is the golden ratio and $\hat\phi$ is its conjugate. ...
Prove the following equality: $\sum_{k=0}^n\binom {n-k }{k} = F_n$ [duplicate]
I need to prove that there is the following equality: $$\sum\limits_{k=0}^n {n-k \choose k} = F_{n}$$ where $F_{n}$ is a n-th Fibonacci number. The problem seems easy but I can't find the way to ...
prove that $\operatorname{fib}(n)<{(5/3)}^n$
I am trying to prove that $$\operatorname{fib}(n)<\left(\frac{5}{3}\right)^n$$ where $\operatorname{fib}(n)$ is the $n^{th}$ fibonacci number. For a proof I used induction, as we know ...