Tagged Questions
6
votes
4answers
707 views
Proof That $1=0$ — Why is it False?
So I devised this proof that $1=0$. Of course it is false, but I don't know why. Why?
$$\begin{align*}
x+1&=y\\
\frac{x+1}{y}&=1\\
\frac{x+1}{y}-1&=0\\
\frac{x+1}{y}-\frac{y}{y}&=0\\
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16
votes
5answers
1k views
Where is the flaw in this argument of a proof that 1=2? (Derivative of repeated addition)
Consider the following:
$1 = 1^2$
$2 + 2 = 2^2$
$3 + 3 + 3 = 3^2$
Therefore,
$\underbrace{x + x + x + \ldots + x}_{x \textrm{ times}}= x^2$
Take the derivative of lhs and rhs and we get:
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