This tag is for questions about divisibility, that is, determining when one thing is a multiple of another thing.

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Mathematical induction [duplicate]

Prove that $9$ divides $n^3 + (n+1)^3 + (n+2)^3$ where $n$ is a nonnegative integer. I have seen many questions on this site that contain the answer to this problem and I already know the solution, ...
1
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5answers
99 views

Proving $9$ divides $n^3 + (n+1)^3 + (n+2)^3$ [duplicate]

I'm trying to prove by MI. I have already distributed n+1, but now I'm stuck on how I can show 9 divides the RHS since $42n$ and $3n^3$ does not divide evenly. ...
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3answers
426 views

Mathematical induction prove that 9 divides $n^3 + (n+1)^3 + (n+2)^3$ . [duplicate]

How can I use mathematical induction to prove that $9$ divides $n^3 + (n+1)^3 + (n+2)^3$ whenever $n$ is a nonnegative integer?
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5answers
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Simple Proof by induction: “9 divides $n^3 + (n+1)^3 + (n+2)^3$”

I'm trying to prove using induction that 9 divides $n^3 + (n+1)^3 + (n+2)^3$ whenever $n$ is a non-negative integer. So far, I have: Base case: P(1) = (1) + (8) + (27) = 36, 36 can be divided by 9 ...
5
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4answers
1k views

How many integers in the range [1,999] are divisible by exactly 1 of 7 and 11?

This is a question in Kenneth Rosen's Discrete Mathematics textbook 6th edition. I haven't had trouble with any other counting problems regarding "how many numbers in range [x,y] have divisibility ...
2
votes
1answer
46 views

Proving $k$ is divisible by $3$ iff the sum of the digits of $k$ is divisible by 3 [duplicate]

I am trying to prove that $k$ is divisible by $3$ iff the sum of the digits of $k$ is divisible by 3 for all $k \in Z$. I am not even sure what tags to use because I am not sure of right methods to ...
12
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7answers
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The product of n consecutive integers is divisible by n factorial

How can we prove that the product of n consecutive integers is divisible by n factorial? Note: In this subsequent question and the comments here the OP has clarified that he seeks a proof that ...
3
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1answer
37 views

Decide if there exist $a$ and $b \in \mathbb{Z}$ such that $a^2=2b^2$.

Decide if there exist $a$ and $b \in \mathbb{Z}$ such that $a^2=2b^2$. $a,b \neq 0$ We have to solve this kinds of problems using the order of a prime function: $v_p(a) \in \mathbb{Z}$ which tells ...
2
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3answers
75 views

$5 \nmid 2^{n}-1$ when $n$ is odd

I want to prove that $$5 \nmid 2^{n}-1$$ where $n$ is odd. I used Fermat's little theorem, which says $2^4 \equiv 1 \pmod 5$, because $n$ is odd then $4 \nmid n$ , so it is done. can you check it ...
0
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3answers
42 views

Find $GCD(n^2+1,n+1)$

$GCD(n^2+1,n+1)$, $n\in \mathbb{N}$ What I did: $n^2+1=(n-1)(n+1) + 0$ So I thought $(n^2+1:n+1)=n+1$ But that doesn't seem to be the case: $n=2$ $n^2+1=5$ $n+1=3$ $GCD(5,3)=1$ Why is the ...
1
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2answers
17 views

Prove the order of the group homomorphism of an element divides the order of the element.

Let $\phi : G \rightarrow H$ be a group homomorphism. Prove $\forall g \in G$, the order of $\phi(g)$ divides $g$. I've gotten to the point where I've shown that if, $ord(\phi(g)) < ord(g)$ then ...
6
votes
2answers
762 views

Fibonacci and Lucas identity

By the trial and error method I have observed the following identity by taking some numerical values. Those are $F_m$|$L_n$ is valid only if one of the following holds. a) $m = 1$ or $m =2$ b) $m ...
1
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1answer
391 views

Proof by induction involving fibonacci numbers

The Fibonacci numbers are defined as follows: $f_0=0$, $f_1=1$, and $f_n=f_{n−1}+f_{n−2}$ for $n≥2$. Prove each of the following three claims: (i) For each $n≥0$, $f_{3n}$ is even. (ii) For each ...
11
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4answers
384 views

Prove: If $\gcd(a,b,c)=1$ then there exists $z$ such that $\gcd(az+b,c) = 1$

I can't crack this one. Prove: If $\gcd(a,b,c)=1$ then there exists $z$ such that $\gcd(az+b,c) = 1$ (the only constraint is that $a,b,c,z \in \mathbb{Z}$).
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3answers
58 views

Let $p$ be a prime. Why is ${p^mn \choose p^m}$, where $p \nmid n$, not divisible by $p$? [duplicate]

Let $p$ be a prime. Why is ${p^mn \choose p^m}$, where $p \nmid n$, not divisible by $p$? $${p^mn \choose p^m} = \frac{(p^mn)!}{p^m!(p^mn-p^m)!} = ...
1
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2answers
28 views

prove that $\forall k\in \mathbb Z$ if $(m,n)=1$(coprimes) then $(k,m,n)=1$

Prove that $\forall k\in \mathbb Z$ if $(m,n)=1$(coprimes) then $(k,m,n)=1$ I did this by contradiction: let $d=(k,m,n)$ so that $d\neq 1$; by definition of greatest common divisor $d|k, d|m, d|n$ ...
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2answers
55 views

For a primitive Pythagorean triple $(a, b, c)$, is it always true that $\gcd(a,b) = \gcd(b,c) = \gcd(a,c) = 1$?

Let $(a, b, c)$ be a primitive Pythagorean triple. I know that $\gcd(a,b,c) = 1$. Is it always true that $\gcd(a,b) = \gcd(b,c) = \gcd(a,c) = 1$?
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6answers
144 views

Euclidean Algorithm Question

So I have been asked to find $d=(a,b)$ when $a=1109$ and $b=4999$ and express $d$ as a linear combination of $a$ and $b$ Well I have worked out that $d=1$ but I am struggling to express $d$ as a ...
2
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4answers
87 views

Prove that if $3|mn$, then $3|m$ or $3|n$

I am trying to prove this for integers $m$ and $n$. I tried to reach prove that $3|m$ by assuming that 3 does not divide $n$, but this is such a basic assumption of mine already that it is hard for ...
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3answers
28 views

Binary remainder not equal to the decimal remainder

I am having a weird result. I am dividing the binary number $10101010100000$ by $10011$. In binary division. I get $R= 0100$ which is 4. However, If I consider the decimal representation of the ...
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2answers
151 views

how $1/0.5$ is equal to $2$?

My question is how $1/0.5$ is equal to $2$. I am not asking the mathematical justification that $1/0.5=10/5=2$. I know all this. I just want to know how it is two... a lay man justification. ...
1
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1answer
89 views

Prove that we always have $ 2n \mid \varphi(m^n+p^n) $

For each $ a ∈ \Bbb N^*$, denoted by $\varphi (a) $ is the number of positive integers not exceeding $a$ and coprime to $a$. Let $n, m, p ∈ \Bbb N^*, m \ne p$. Prove that we always have $2n \mid ...
1
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1answer
31 views

Finding a natural number $k>1$ such that $k$ divides $(26+35n)$ and $(3+7n)$

I am trying to find a natural number $k>1$ such that $k$ divides $(26+35n)$ and $k$ divides $(3+7n)$ for some integer $n$. I know that $(ka)=(26+35n)$ for some $a \in Z$ and $(kb)=(3+7n)$ for some ...
6
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2answers
493 views

Divisibility for 7

I have seen other criteria for divisibility by 7. Criterion described below present in the book Handbook of Mathematics for IN Bronshtein (p. 323) is interesting, but could not prove it. Let $n = ...
10
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3answers
180 views

Showing that $a^n - 1 \mid a^m - 1 \iff n \mid m$

Let $a\ge 2$ be an integer. Show that for positive integers $m,n$, we have $a^n - 1$ divides $a^m - 1$ if and only if $n$ divides $m$. I am having trouble showing this. I've seen a similar ...
0
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1answer
45 views

If $m\mid n$ then $p^m-1\mid p^n-1$ [duplicate]

I know $m$ ,$n$ are two positive integer numbers such that $m\mid n$. If $p$ is a prime number, I want to show $p^m-1\mid p^n-1$.
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3answers
32 views

How to formally prove: if $d\mid da+b$, then $d\mid b$?

How would I formally prove that for the integers $a$, $b$, and $d$, if $d\mid da+b$, then $d\mid b$? Would a direct proof be the best option? If I do a direct proof I seem to get stuck pretty ...
0
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1answer
23 views

Divisibility in a certain ring and divisibility in integers.

Divisibility in the ring $\mathbb{Z}[x,y]$ implies divisibility in $\mathbb{Z}$ ? Let $P(x,y)=Q(x,y)\cdot R(x,y)$ with $P,Q,R$ polynomials with integer coefficients, evaluating in $(x,y)=(a,b)$ with ...
2
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3answers
50 views

Proving gcd($a,b$)lcm($a,b$) = $|ab|$

I was trying to prove that $$ dm = |ab|$$ where $d$ = gcd(a,b) and m = lcm(a,b). So I went about by saying that $a = p_1p_2...p_n$ where each $p_n$ is a prime. Same applies to $b = q_1q_2 ... q_c$. ...
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0answers
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Generalisation of $\gcd\left(\frac{a^n-b^n}{a-b},a-b\right)=\gcd(n\gcd(a,b)^{n-1},a-b)$ to $\gcd\left(\frac{a^n-b^n}{a-b},a^m-b^m\right)$?

We have the identity $$\gcd\left(\frac{a^n-b^n}{a-b},a-b\right)=\gcd(n\gcd(a,b)^{n-1},a-b).$$ (see here) This appears to be a quite useful result with various applications. I wonder whether there is ...
2
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4answers
73 views

Prove if $7\mid a^2+b^2 \longrightarrow 7\mid a$ and $ 7\mid b$

Prove if $7\mid a^2+b^2 \longrightarrow 7\mid a$ and $7\mid b$ What I did: I found the possible remainders for $a^2$ are $0, 1, 2$ and $4$. I think I should say $r_7(a^2)+r_7(b^2)$ can't equal any ...
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0answers
37 views

On odd perfect numbers $N$ given in the Eulerian form $N = {q^k}{n^2}$, Part II

(Note: This has been cross-posted to MO.) A positive integer $N$ is said to be perfect if $\sigma(N) = 2N$, where $\sigma(x)$ is the sum of the divisors of $x$. An odd perfect number $N$ is said to ...
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0answers
37 views

Existence of non-coprime between an integer and an arithmetic sequence

Take two relatively prime numbers $m,n \in \mathbb{Z}$ (i.e. $gcd(m,n) = 1$) where $m \neq 1$. Show that: $$\forall a \in \mathbb{Z} \textrm{ s.t. } 0<a<n$$ $$\exists i \in \mathbb{Z^+} ...
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2answers
35 views

A question related to the concept of being “relatively prime”

Suppose that I have $a, b, c, d \in \mathbb{N}$, where $\mathbb{N}$ is the set of natural numbers. If I have the equation $ab = 2cd$ and I know that $\gcd(a,c)=\gcd(c,d)=1$, then it follows that I ...
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5answers
236 views

Show {$ ax + by | x, y \in \mathbb{Z}$} = {$n$ gcd$(a,b)|n\in \mathbb{Z}$}

I have the following problem: Let $a, b \in\mathbb{Z}$. Show that {$ ax + by | x, y \in \mathbb{Z}$} = {$n$ gcd$(a,b)|n\in \mathbb{Z}$} I understand that the Bezout's lemma says that $gcd(a,b) = ...
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5answers
4k views

Prove $\gcd(a+b, a-b) = 1$ or $\gcd(a+b, a-b) = 2$ if $\gcd(a,b) = 1$

I want to show that for $\gcd(a,b) = 1$ $a,b \in Z$ $\gcd(a+b, a-b) > = 1$ or $\gcd(a+b, a-b) = 2$ holds. I think the first step should look something like this: $d = \gcd(a+b, a-b) ...
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0answers
50 views

Prove that $\{ ax+by\mid x,y\in\mathbb Z\} = \{ n(a,b) \mid n\in\mathbb Z\}$ [duplicate]

Prove the following proposition: Suppose $a,b$ are fixed integers. Then $\{ ax+by\mid x,y\in\mathbb Z\} = \{ n(a,b) \mid n\in\mathbb Z\}$.
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2answers
55 views

If $n$ is a positive integer such that $2^n+n^2$ is a prime number , then is it true that $6|n-3$ ?

If $n$ is a positive integer such that $2^n+n^2$ is a prime number , then is it true that $6|n-3$ ? Trivially $n$ cannot be even , so this leaves us only with the possibilities $n \equiv1,3,5( \mod 6) ...
2
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3answers
61 views

Number Theory Simple Proof Confusion

Suppose that c|ab and (b, c) = 1. Then c|a Proof (ab, ac) =|a|(b, c) = |a|. But by hypothesis, one has c|ab, which implies that c|(ab, ac). We thus conclude that c|a. And the proof is complete. I am ...
2
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2answers
91 views

Proving $2^{2^n}+3^{2^n}+5^{2^n}$ is divisible by $19$ for all $n\geq 1$ by induction

I came across the following in the book Handbook of Mathematical Induction: $$ 19\mid (2^{2^n}+3^{2^n}+5^{2^n}),\quad n\in\mathbb{Z^+}\tag{1} $$ Apparently, this problem is not so bad if you think ...
2
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1answer
27 views

Number of bounded divisors of an integer

Given integers $n,t$, what is an upper bound for the number of integers dividing $n$ in the interval $\{1,\ldots,t\}$? When $t=n$ this boils down to the classical divisor bound ...
0
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2answers
82 views

If a prime $p\mid b$ and $a^2=b^3$, then $p^3\mid a$

I have an exercise that I don't know how to solve. I tried to solve it in many ways, but I didn't get any progress in proving or disproving this... The exercise is: Prove or disprove: if $p$ is a ...
0
votes
2answers
60 views

If $d$ divides $k$ and $d$ divides $n$, then $d$ divides $(8k - 3n)$

Suppose that $k$, $n$, and $d$ are integers and $d$ is not $0$. Prove: If $d$ divides $k$ and $d$ divides $n$, then $d$ divides $(8k - 3n)$. You may not use the theorem stating the following: Let ...
12
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3answers
348 views

Mental Primality Testing

At a trivia night, the following question was posed: "What is the smallest 5 digit prime?" Teams (of 4) were given about a minute to write down their answer to the question. Obviously, the answer is ...
2
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0answers
28 views

$m+n = (n,m)^2; n+l = (n,l)^2; l+m = (m,l)^2$

Find all natural numbers $m,n,l$ such that $$m+n = (n,m)^2; \quad n+l = (n,l)^2; \quad l+m = (m,l)^2$$ where $(a,b)$ is the greatest common divisor of $a$ and $b$. I only managed to find that if ...
1
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2answers
46 views

Proof that $(2^m - 1, 2^n - 1) = 2^d - 1$ where $d = (m,n)$ [duplicate]

$(2^m - 1, 2^n - 1) = 2^d - 1$ where $d = (m,n)$ my work: I assumed m = da , n = db for a,b $\in$ Z. Now, $2^m - 1$ = $2^{da} - 1$ = $(2^d)^a - 1$ = $x^a - 1$ where $x = 2^d$. similarly $2^n - 1$ = ...
3
votes
5answers
124 views

How can I show that $\phi(m) \mid \phi(n)$? [duplicate]

I want to prove that: $$\text{ if } m,n \geq 1 \text{ and } m \mid n,\text{ then } \phi(m) \mid \phi(n).$$ How can I show this? I thought the following: $$m \mid n \Rightarrow \exists k \in ...
2
votes
2answers
138 views

Proving $\phi(m)|\phi(n)$ whenever $m|n$ [duplicate]

Show that $\varphi(m)|\varphi(n) $ whenever $m|n$. I am stuck after writing the formula. I know that if $m$ divides $n$, that means one of the prime factors of $n$ would include $m$ or a multiple of ...
1
vote
1answer
63 views

Greatest integer which divides $2001\times\ 2002\times 2003\times\ \cdots\times\ 2009$

Here i have a problem. Find the greatest integer which divides $2001\times\ 2002\times 2003\times\ \cdots\times\ 2009$. I couldn't get the problem actually, how to start with?