This tag is for questions about divisibility, that is, determining when one thing is a multiple of another thing.

learn more… | top users | synonyms

-1
votes
2answers
249 views

Divisibility of prime numbers

I have this exercise in my worksheet in the discrete mathematics course.I don't understand the part that deals with prime numbers in integer-divisibility. "Show that for a prime number $p$, if a ...
96
votes
8answers
14k views

Are half of all numbers odd?

Plato puts the following words in Socrates' mouth in the Phaedo dialogue: I mean, for instance, the number three, and there are many other examples. Take the case of three; do you not think it may ...
9
votes
3answers
2k views

Divisibility rules and congruences

Sorry if the question is old but I wasn't able to figure out the answer yet. I know that there are a lot of divisibility rules, ie: sum of digits, alternate plus and minus digits, etc... but how can ...
6
votes
5answers
2k views

Proving prime $p$ divides $\binom{p}{k}$ for $k\in\{1,\ldots,p-1\}$. [closed]

Prove if $p$ is a prime then $p \,| \binom{p}{k}$ for $k\in\{1,\ldots,p-1\}$ I don't really know where to begin with this one.
1
vote
4answers
513 views

Suppose $(a,b)=1$, then $(2a+b,a+2b)=1\text{ or }3$.

Suppose $(a,b)=1$. Let $d=(2a+b,a+2b)$. Then $d=(2a+b)u+(a+2b)v=a(2u+v)+b(2v+u)$ where $u,v \in \mathbb{Z}$. Since $(a,b)=1$, then $a(2u+v)+b(2v+u)=1$. I'm not sure if I'm going in the right ...
9
votes
12answers
5k views

If $\gcd(a,b)=1$, then $\gcd(a^n,b^n)=1$

If $\gcd(a,b)=1$, then $\gcd(a^n,b^n)=1$ This seems clear, but I don't know how to prove this.. I was trying to show this by induction such that if $a^{n+1}$ = $rs$ and $b^{n+1}$ = $rt$, then ...
9
votes
2answers
3k views

Divisibility Rules for Bases other than $10$

I still remember the feeling, when I learned that a number is divisible by $3$, if the digit sum is divisible by $3$. The general way to get these rules for the regular decimal system is ...
10
votes
3answers
458 views

Does $a^n \mid b^n$ imply $a\mid b$?

Does $a^n \mid b^n$ imply $a\mid b$? I think it does but haven't been able to prove it. I don't know much number theory so an elementary answer would be great.
5
votes
2answers
5k views

Proof of $\gcd(a,b)=ax+by$

Here is my proof of $\gcd(a,b)=ax+by$ for $a, b, x, y \in \mathbb{Z}$. Am I doing something wrong? Are there easier proofs? $a,b \in \mathbb{Z}, g=\gcd(a,b)$ and suppose $g \neq ax + by$. Let $c$ be ...
1
vote
4answers
171 views

If $\gcd(a,n) = 1$ and $\gcd(b,n) = 1$, then $\gcd(ab,n) = 1$.

If $\gcd(a,n) = 1$ and $\gcd(b,n) = 1$, then $\gcd(ab,n) = 1$. Also... $a,b$ and $n$ are natural numbers. I feel I should begin with EEA to multiply out the gcd's, but I don't know where to go from ...
15
votes
7answers
730 views

$n^5-n$ is divisible by $10$?

I was trying to prove this, and I realized that this is essentially a statement that $n^5$ has the same last digit as $n$, and to prove this it is sufficient to calculate $n^5$ for $0-9$ and see that ...
8
votes
8answers
501 views

Prove that if $3\mid a^2+b^2$ then $3\mid a$ and $3\mid b$.

For elements $a$ and $b$ in the ring $\Bbb{Z}$ prove that if $3\mid a^2+b^2$ then $3\mid a$ and $3\mid b$. I tried proving it but I just don't manage to. Maybe I am missing some basic claims in the ...
4
votes
1answer
3k views

Sum of GCD(k,n)

I want to find this $$ \sum_{k=1}^n \gcd(k,n)$$ but I don't know how to solve. Does anybody can help me to finding this problem. Thanks.
2
votes
2answers
877 views

Prove that $x^3 \equiv x \bmod 6$ for all integers $x$

Prove that $x^3 \equiv x \bmod 6$ for all integers $x$ I think I got it, but is this proof correct? We can write any integer x in the form: $x = 6k, x = 6k + 1, x = 6k + 2, x = 6k + 3, x = 6k + ...
1
vote
3answers
81 views

If $\gcd (a,b) = 1$, what can be said about $\gcd (a+b,a-b)$?

Suppose $a, b \in \mathbb{Z}$, $a > b$, and $\gcd (a,b) = 1$. What can be said about $\gcd (a+b,a-b)$? Is it true in general that $\gcd (a+b,a-b) \leq 2$?
1
vote
1answer
73 views

Is it possible to find $n-1$ consecutive composite integers

Given an integer $n\geq 2$ ,can we always find an integer $m$ such that each of the $n-1$ consecutive integers $m+2,m+3,.....,m+n$ are composite?
1
vote
4answers
186 views

$(a^{n},b^{n})=(a,b)^{n}$ and $[a^{n},b^{n}]=[a,b]^{n}$?

How to show that $$(a^{n},b^{n})=(a,b)^{n}$$ and $$[a^{n},b^{n}]=[a,b]^{n}$$ without using modular arithmetic? Seems to have very interesting applications.$$$$Try: $(a^{n},b^{n})=d\Longrightarrow ...
5
votes
1answer
8k views

Prove by mathematical induction that $n^3 - n$ is divisible by $3$ for all natural number $n$

I'm working on a task where I'm a bit unsure if the answer I've got is correct. Here is the task: Show by induction that the following assertion is true for all natural numbers $n$ $n^3 - ...
4
votes
3answers
2k views

Show that $\gcd(a,bc)=1$ if and only if $\gcd(a,b)=1$ and $\gcd(a,c)=1$

Show that $\gcd(a,bc)=1$ if and only if $\gcd(a,b)=1$ and $\gcd(a,c)=1$. I am new at proofs and I think I should use Euclid's Lemma which states "If $p$ is a prime that divides $ab$, then $p$ divides ...
4
votes
3answers
527 views

Prove that $(a+1)(a+2)…(a+b)$ is divisible by $b!$ [duplicate]

The problem is following, prove that: $$(a+1)(a+2)...(a+b)\text{ is divisible by } b!\text{ for every positive integer a,b}$$ I've tried solving this problem using mathematical induction, but I ...
3
votes
2answers
138 views

Does $\gcd(a,bc)$ divides $\gcd(a, b)\gcd(a, c)$?

I want to prove that $\gcd(a,bc)$ divides $\gcd(a,b)\gcd(a,c)$ but I can't succeed. I tried to go with $\gcd(a,b) = sa+tb$ and it didn't work, tried to use the fact that $\gcd(a,b)$ and $\gcd ...
3
votes
6answers
286 views

Prove that $6$ divides $n(n + 1)(n + 2)$

I am stuck on this problem, and was wondering if anyone could help me out with this. The question is as follows: Let $n$ be an integer such that $n ≥ 1$. Prove that $6$ divides $n(n + 1)(n + 2)$. ...
2
votes
3answers
84 views

Proof that if $\gcd(a,b) = 1$ and $a\mid n$ and $b\mid n$, $ab \mid n$

I'm learning about properties of greatest common divisors, specifically when two numbers are relatively prime. The exercise I'm working through is : Suppose that $\gcd(a,b) = 1$ and that $a\mid ...
2
votes
2answers
159 views

Prime elements in the gaussian integers

Prove: If a prime number $p\in \mathbb N$ is from the form $p=4k+3,k\in \mathbb N$, then its also a prime number in $\mathbb Z[i]$,i.e. if $p|(z_1\cdot z_2)$ then $p|z_1$ or $p|z_2$. I dont have any ...
0
votes
3answers
76 views

Prove that gcd(e,f)=1

could someone please help me with this proof? Suppose that a, b ∈ N, and d = gcd(a, b). Since d divides a, we have a = de for some integer e, and similarly b = df for some integer f. Prove that ...
43
votes
4answers
2k views

How does the divisibility graphs work?

I came across this graphic method for checking divisibility by $7$. $\hskip1.5in$ Write down a number $n$. Start at the small white node at the bottom of the graph. For each digit $d$ in ...
25
votes
8answers
628 views

Prove that $(mn)!$ is divisible by $(n!)\cdot(m!)^n$

Prove that $$(n!)\cdot(m!)^n|(mn)!$$ I can prove it using Legendre's Formula, but I have to use the lemma that $$ ...
18
votes
2answers
507 views

Do there exist two primes $p<q$ such that $p^n-1\mid q^n-1$ for infinitely many $n$?

We can prove that there is no integer $n>1$ such that $2^n-1\mid 3^n-1$. This leads to the following question: Is it true that for every pair of primes $p<q$ there are only finitely many ...
18
votes
3answers
1k views

Proving there are an infinite number of pairs of positive integers $(m,n)$ such that $\frac{m+1}{n}+\frac{n+1}{m}$ is a positive integer

The question is: Show that there are an infinite number of pairs $(m,n): m, n \in \mathbb{Z}^{+}$, such that: $$\frac{m+1}{n}+\frac{n+1}{m} \in \mathbb{Z}^{+}$$ I started off approaching this ...
11
votes
2answers
507 views

How does one attack a divisibility problem like $(a+b)^2 \mid (2a^3+6a^2b+1)$?

In my current line of investigation, I am running into [many] divisibility questions like the one in the title, i.e. $$ (a+b)^2 \mid (2a^3+6a^2b+1), \qquad(\star) $$ where $a > b \ge 1$ are ...
12
votes
2answers
2k views

Elementary proof of Zsigmondy's theorem

I've been writing a not-so-short introduction to elementary number theory, supplying proofs for all theorems. When coming across Zsigmondy's theorem, it seemed difficult to find a proof available on ...
4
votes
1answer
284 views

Divisibility of $2^n - 1$ by $2^{m+n} - 3^m$.

For what values of $m,n$ natural, do $2^n - 1$ is divisible by $2^{m+n} - 3^m$? Thank you very much.
13
votes
6answers
2k views

Proof: if $p$ is prime, and $0<k<p$ then $p$ divides $\binom pk$ [duplicate]

Question : If $p$ is prime, and $0< k< p$ show that $ p \mid {p \choose k}$ ${p \choose k}$ can be rewritten as: $${p(p-1)(p-2)\dots(p-(k-1))(p-k)! \over (p-k)!\cdot ...
2
votes
4answers
176 views

Division of $q^n-1$ by $q^m-1$, in Wedderburn's theorem

I need this for a proof of Wedderburn's theorem: $$q^m - 1 | q^n - 1 \quad \Rightarrow \quad m|n$$ with $q>1 \in \mathbf{N}$ and $m,n \in \mathbf{N}$. I'd also like to know if it works the other ...
7
votes
2answers
201 views

$n\mid \phi(a^{n}-1)$ for any $a>n$?

I saw the proof which goes as follows: $a^{n} \equiv 1 \pmod{a^{n}-1} $, and $n$ is the smallest power of a such that this is true. We also know that by Euler's Identity $a^{\phi(a^{n}-1)}\equiv ...
3
votes
1answer
107 views

Determine the divisibility of a given number without performing full division

My question is slightly more complicated than what's implied on the title, so I will start with an example. Given any number $N$ on base $10$, we can easily determine whether or not $N$ is divisible ...
2
votes
3answers
540 views

Prove that distinct Fermat Numbers are relatively prime [duplicate]

The Fermat numbers are defined by $F_m = 2^{2^m} + 1$. Prove that for $m \ne n$ we have $(F_m, F_n) = 1$. I have to first prove that $F_{m+1} = F_0F_1 \cdots F_m + 2$ by representing $F_{m+1}$ in ...
2
votes
3answers
118 views

Divisor in $\mathbb{C}[X]$ $\implies$ divisor in $\mathbb{R}[X]$?

let $P \in \mathbb{R}[X]$ be a real polynomial divisible by a polynomial $Q \in \mathbb{R}[X]$ in $\mathbb{C}[X]$. How can I easily show that $P$ is also divisible by $Q$ in $\mathbb{R}[X]$? A simple ...
11
votes
2answers
281 views

Show that $A[X]/(aX+b)$ is an integral domain

Let $A$ be an integral domain, $a$ and $b \in A-\{0\}$, and let $B = A[X]/(aX+b)$. Show that, if $Aa \cap Ab=Aab$, then $B$ is an integral domain. My attempt at proof (following a hint). Denote ...
8
votes
1answer
980 views

Smallest number with a given number of factors

From my rather rudimentary explorations of this fascinating problem, I believe it to be a layered and rewarding subject for investigation. My question, essentially, is: How do you find the smallest ...
6
votes
4answers
3k views

Prove $\gcd(a+b,a^2+b^2)$ is $1$ or $2$ if $\gcd(a,b) = 1$

Assuming that $\gcd(a,b) = 1$, prove that $\gcd(a+b,a^2+b^2) = 1$ or $2$. I tried this problem and ended up with $$d\mid 2a^2,\quad d\mid 2b^2$$ where $d = \gcd(a+b,a^2+b^2)$, but then I am ...
5
votes
7answers
315 views

Prove that if $n^2$ is divided by 3, then also $n$ can also be divided by 3.

$n\in \Bbb N$ Prove that if $n^2$ is divided by 3, then also n can also be divided by 3. I started solving this by induction, but I'm not sure that I'm going in the right direction, any ...
5
votes
4answers
4k views

How to prove gcd of consecutive Fibonacci numbers is 1? [duplicate]

Possible Duplicate: Prove that two any consecutive terms of Fibonacci sequence are relatively prime How to prove it ? Can you help me ? Let $f_n$ be Fibonacci Sequence. ...
3
votes
2answers
83 views

Prove that $\gcd(a^2, b^2) = \gcd(a, b)^2$ [duplicate]

The problem's quite clear. Prove that $$\gcd(a^2, b^2) = \gcd(a, b)^2$$ This is easy to understand intuitively and using the Fundamental Theorem of Arithmetic would be easy but I want to prove it by ...
3
votes
3answers
477 views

Prove that $n$ divides $\phi(a^n -1)$ where $a, n$ are positive integer without using concepts of abstract algebra

I need to show that $n$ divides $\phi(a^n -1)$ where $a, n$ are positive integer without using concepts of abstract algebra I know that $$a^n\equiv 1\pmod {a^n-1}$$ How do I proceed from there?
2
votes
3answers
131 views

Let $a,b$ be positive integers such that $a\mid b^2 , b^2\mid a^3 , a^3\mid b^4 \ldots$ so on , then $a=b$?

Let $a,b$ be positive integers such that $a\mid b^2 , b^2\mid a^3 , a^3\mid b^4 \ldots$ that is $a^{2n-1}\mid b^{2n} ; b^{2n}\mid a^{2n+1} , \forall n \in \mathbb Z^+$ , then is it true that $a=b$ ?
1
vote
2answers
55 views

Prove that $τ(m^n)$ and $n$ are coprime $(m,n ∈ N^+)$

We have that $τ(n)=\sum_{d|n} 1$ is the number of dividers of n. Dividers of $m^n$ are $1,m,m^2,...,m^n$ then we have that $τ(m^n)=n+1$. Is this correct so far? Now we must prove that $τ(m^n)$ and ...
1
vote
2answers
743 views

Show that if $a$ and $b$ are positive integers with $(a,b)=1$ then $(a^n, b^n) = 1$ for all positive integers n [duplicate]

Show that if $a$ and $b$ are positive integers with $(a,b)=1$ then $(a^n, b^n) = 1$ for all positive integers n Hi everyone, for the proof to the above question, Can I assume that since $(a, b) = ...
0
votes
3answers
1k views

How to show that $\gcd(n! + 1, (n + 1)! + 1) \mid n$?

Let $n$ be a positive integer, $n!$ denotes the factorial of $n$. Let $d = \gcd(n! + 1, (n + 1)! + 1)$. Show that $d$ divides $n$. (Hint: notice that $(n+1)(n!+1) = (n+1)!+n+1$)
6
votes
2answers
143 views

Prove or disprove : $a^3\mid b^2 \Rightarrow a\mid b$

I think it's true, because I can't see counterexamples. Here's a proof that I am not sure of: Let $p_1,p_2,\ldots, p_n$ be the prime factors of $a$ or $b$ \begin{eqnarray} a&=& ...