This tag is for questions about divisibility, that is, determining when one thing is a multiple of another thing.

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8
votes
8answers
489 views

Prove that if $3\mid a^2+b^2$ then $3\mid a$ and $3\mid b$.

For elements $a$ and $b$ in the ring $\Bbb{Z}$ prove that if $3\mid a^2+b^2$ then $3\mid a$ and $3\mid b$. I tried proving it but I just don't manage to. Maybe I am missing some basic claims in the ...
4
votes
1answer
3k views

Sum of GCD(k,n)

I want to find this $$ \sum_{k=1}^n \gcd(k,n)$$ but I don't know how to solve. Does anybody can help me to finding this problem. Thanks.
2
votes
2answers
820 views

Prove that $x^3 \equiv x \bmod 6$ for all integers $x$

Prove that $x^3 \equiv x \bmod 6$ for all integers $x$ I think I got it, but is this proof correct? We can write any integer x in the form: $x = 6k, x = 6k + 1, x = 6k + 2, x = 6k + 3, x = 6k + ...
1
vote
3answers
81 views

If $\gcd (a,b) = 1$, what can be said about $\gcd (a+b,a-b)$?

Suppose $a, b \in \mathbb{Z}$, $a > b$, and $\gcd (a,b) = 1$. What can be said about $\gcd (a+b,a-b)$? Is it true in general that $\gcd (a+b,a-b) \leq 2$?
1
vote
1answer
73 views

Is it possible to find $n-1$ consecutive composite integers

Given an integer $n\geq 2$ ,can we always find an integer $m$ such that each of the $n-1$ consecutive integers $m+2,m+3,.....,m+n$ are composite?
6
votes
3answers
328 views

For integers $a$ and $b$, $ab=\text{lcm}(a,b)\cdot\text{hcf}(a,b)$

I was reading a text book and came across the following: Important Results (This comes immediately after LCM:) If 2 [integers] $a$ and $b$ are given, and their $LCM$ and $HCF$ are $L$ and ...
5
votes
1answer
7k views

Prove by mathematical induction that $n^3 - n$ is divisible by $3$ for all natural number $n$

I'm working on a task where I'm a bit unsure if the answer I've got is correct. Here is the task: Show by induction that the following assertion is true for all natural numbers $n$ $n^3 - ...
4
votes
3answers
2k views

Show that $\gcd(a,bc)=1$ if and only if $\gcd(a,b)=1$ and $\gcd(a,c)=1$

Show that $\gcd(a,bc)=1$ if and only if $\gcd(a,b)=1$ and $\gcd(a,c)=1$. I am new at proofs and I think I should use Euclid's Lemma which states "If $p$ is a prime that divides $ab$, then $p$ divides ...
3
votes
2answers
119 views

Does $\gcd(a,bc)$ divides $\gcd(a, b)\gcd(a, c)$?

I want to prove that $\gcd(a,bc)$ divides $\gcd(a,b)\gcd(a,c)$ but I can't succeed. I tried to go with $\gcd(a,b) = sa+tb$ and it didn't work, tried to use the fact that $\gcd(a,b)$ and $\gcd ...
3
votes
6answers
204 views

Prove that $6$ divides $n(n + 1)(n + 2)$

I am stuck on this problem, and was wondering if anyone could help me out with this. The question is as follows: Let $n$ be an integer such that $n ≥ 1$. Prove that $6$ divides $n(n + 1)(n + 2)$. ...
2
votes
3answers
79 views

Proof that if $\gcd(a,b) = 1$ and $a\mid n$ and $b\mid n$, $ab \mid n$

I'm learning about properties of greatest common divisors, specifically when two numbers are relatively prime. The exercise I'm working through is : Suppose that $\gcd(a,b) = 1$ and that $a\mid ...
0
votes
3answers
67 views

Prove that gcd(e,f)=1

could someone please help me with this proof? Suppose that a, b ∈ N, and d = gcd(a, b). Since d divides a, we have a = de for some integer e, and similarly b = df for some integer f. Prove that ...
43
votes
4answers
2k views

How does the divisibility graphs work?

I came across this graphic method for checking divisibility by $7$. $\hskip1.5in$ Write down a number $n$. Start at the small white node at the bottom of the graph. For each digit $d$ in ...
18
votes
2answers
482 views

Do there exist two primes $p<q$ such that $p^n-1\mid q^n-1$ for infinitely many $n$?

We can prove that there is no integer $n>1$ such that $2^n-1\mid 3^n-1$. This leads to the following question: Is it true that for every pair of primes $p<q$ there are only finitely many ...
43
votes
8answers
4k views

What is $\gcd(0,0)$?

What is the greatest common divisor of $0$ and $0$? On the one hand, Wolfram Alpha says that it is $0$; on the other hand, it also claims that $100$ divides $0$, so $100$ should be a greater common ...
11
votes
2answers
503 views

How does one attack a divisibility problem like $(a+b)^2 \mid (2a^3+6a^2b+1)$?

In my current line of investigation, I am running into [many] divisibility questions like the one in the title, i.e. $$ (a+b)^2 \mid (2a^3+6a^2b+1), \qquad(\star) $$ where $a > b \ge 1$ are ...
18
votes
3answers
1k views

Proving there are an infinite number of pairs of positive integers $(m,n)$ such that $\frac{m+1}{n}+\frac{n+1}{m}$ is a positive integer

The question is: Show that there are an infinite number of pairs $(m,n): m, n \in \mathbb{Z}^{+}$, such that: $$\frac{m+1}{n}+\frac{n+1}{m} \in \mathbb{Z}^{+}$$ I started off approaching this ...
12
votes
2answers
1k views

Elementary proof of Zsigmondy's theorem

I've been writing a not-so-short introduction to elementary number theory, supplying proofs for all theorems. When coming across Zsigmondy's theorem, it seemed difficult to find a proof available on ...
4
votes
1answer
283 views

Divisibility of $2^n - 1$ by $2^{m+n} - 3^m$.

For what values of $m,n$ natural, do $2^n - 1$ is divisible by $2^{m+n} - 3^m$? Thank you very much.
10
votes
5answers
343 views

Prove that $b\mid a \implies (n^b-1)\mid (n^a-1)$

Given natural numbers $a,b,n$, prove $b\mid a \implies (n^b-1)\mid (n^a-1)$. I tried the simple method of beginning with $b\mid a \implies \exists k \in \mathbb{N} $ such that $bk=a$ and then ...
12
votes
6answers
1k views

Proof: if $p$ is prime, and $0<k<p$ then $p$ divides $\binom pk$ [duplicate]

Question : If $p$ is prime, and $0< k< p$ show that $ p \mid {p \choose k}$ ${p \choose k}$ can be rewritten as: $${p(p-1)(p-2)\dots(p-(k-1))(p-k)! \over (p-k)!\cdot ...
10
votes
3answers
434 views

Does $a^n \mid b^n$ imply $a\mid b$?

Does $a^n \mid b^n$ imply $a\mid b$? I think it does but haven't been able to prove it. I don't know much number theory so an elementary answer would be great.
7
votes
2answers
196 views

$n\mid \phi(a^{n}-1)$ for any $a>n$?

I saw the proof which goes as follows: $a^{n} \equiv 1 \pmod{a^{n}-1} $, and $n$ is the smallest power of a such that this is true. We also know that by Euler's Identity $a^{\phi(a^{n}-1)}\equiv ...
3
votes
1answer
99 views

Determine the divisibility of a given number without performing full division

My question is slightly more complicated than what's implied on the title, so I will start with an example. Given any number $N$ on base $10$, we can easily determine whether or not $N$ is divisible ...
2
votes
4answers
176 views

Division of $q^n-1$ by $q^m-1$, in Wedderburn's theorem

I need this for a proof of Wedderburn's theorem: $$q^m - 1 | q^n - 1 \quad \Rightarrow \quad m|n$$ with $q>1 \in \mathbf{N}$ and $m,n \in \mathbf{N}$. I'd also like to know if it works the other ...
3
votes
3answers
411 views

Prove that $n$ divides $\phi(a^n -1)$ where $a, n$ are positive integer without using concepts of abstract algebra

I need to show that $n$ divides $\phi(a^n -1)$ where $a, n$ are positive integer without using concepts of abstract algebra I know that $$a^n\equiv 1\pmod {a^n-1}$$ How do I proceed from there?
2
votes
3answers
419 views

Prove that distinct Fermat Numbers are relatively prime [duplicate]

The Fermat numbers are defined by $F_m = 2^{2^m} + 1$. Prove that for $m \ne n$ we have $(F_m, F_n) = 1$. I have to first prove that $F_{m+1} = F_0F_1 \cdots F_m + 2$ by representing $F_{m+1}$ in ...
2
votes
3answers
118 views

Divisor in $\mathbb{C}[X]$ $\implies$ divisor in $\mathbb{R}[X]$?

let $P \in \mathbb{R}[X]$ be a real polynomial divisible by a polynomial $Q \in \mathbb{R}[X]$ in $\mathbb{C}[X]$. How can I easily show that $P$ is also divisible by $Q$ in $\mathbb{R}[X]$? A simple ...
11
votes
2answers
278 views

Show that $A[X]/(aX+b)$ is an integral domain

Let $A$ be an integral domain, $a$ and $b \in A-\{0\}$, and let $B = A[X]/(aX+b)$. Show that, if $Aa \cap Ab=Aab$, then $B$ is an integral domain. My attempt at proof (following a hint). Denote ...
8
votes
1answer
962 views

Smallest number with a given number of factors

From my rather rudimentary explorations of this fascinating problem, I believe it to be a layered and rewarding subject for investigation. My question, essentially, is: How do you find the smallest ...
5
votes
3answers
4k views

If $2^n - 1$ is prime from some integer $n$, prove that n must also be prime.

I understand the idea of the proof. I just want to make sure I wrote my proof well. Suppose $n$ is not prime. Then $\exists x,y \in \mathbb{Z}$ such that $n = xy$. $2^{xy} - 1 = (2^x)^y - 1$ $ = ...
4
votes
5answers
206 views

If $\gcd(a,b)=1$ then, $\gcd(a^2,b^2)=1$ [duplicate]

Prove or disprove 'If $\gcd(a,b)=1$ then, $\gcd(a^2,b^2)=1$, with $a,b\not= 0$' I need to prove this statement. I think it is true and also the converse is true. I took some examples such as ...
4
votes
3answers
506 views

Prove that $(a+1)(a+2)…(a+b)$ is divisible by $b!$ [duplicate]

The problem is following, prove that: $$(a+1)(a+2)...(a+b)\text{ is divisible by } b!\text{ for every positive integer a,b}$$ I've tried solving this problem using mathematical induction, but I ...
3
votes
6answers
268 views

How to show that $2730\mid n^{13}-n\;\;\forall n\in\mathbb{N}$

Show that $2730\mid n^{13}-n,\;\;\forall n\in\mathbb{N}$ I tried, $2730=13\cdot5\cdot7\cdot3\cdot2$ We have $13\mid n^{13}-n$, by Fermat's Little Theorem. We have $2\mid n^{13}-n$, by if $n$ ...
2
votes
3answers
119 views

Let $a,b$ be positive integers such that $a\mid b^2 , b^2\mid a^3 , a^3\mid b^4 \ldots$ so on , then $a=b$?

Let $a,b$ be positive integers such that $a\mid b^2 , b^2\mid a^3 , a^3\mid b^4 \ldots$ that is $a^{2n-1}\mid b^{2n} ; b^{2n}\mid a^{2n+1} , \forall n \in \mathbb Z^+$ , then is it true that $a=b$ ?
1
vote
2answers
54 views

Prove that $τ(m^n)$ and $n$ are coprime $(m,n ∈ N^+)$

We have that $τ(n)=\sum_{d|n} 1$ is the number of dividers of n. Dividers of $m^n$ are $1,m,m^2,...,m^n$ then we have that $τ(m^n)=n+1$. Is this correct so far? Now we must prove that $τ(m^n)$ and ...
1
vote
2answers
63 views

If I remove the premise $a\neq b$ in this question, will the statement still be true?

I encountered this proving problem, I can do the proof but my question is why in the condition/premise we need $a$ to be unequal to $b$? My guess is that even $a=b$, the statement is still true, is it ...
1
vote
5answers
382 views

$24\mid n(n^{2}-1)(3n+2)$ for all $n$ natural problems in the statement.

"Prove that for every $ n $ natural, $24\mid n(n^2-1)(3n+2)$" Resolution: $$24\mid n(n^2-1)(3n+2)$$if$$3\cdot8\mid n(n^2-1)(3n+2)$$since$$n(n^2-1)(3n+2)=(n-1)n(n+1)(3n+2)\Rightarrow3\mid ...
0
votes
3answers
1k views

How to show that $\gcd(n! + 1, (n + 1)! + 1) \mid n$?

Let $n$ be a positive integer, $n!$ denotes the factorial of $n$. Let $d = \gcd(n! + 1, (n + 1)! + 1)$. Show that $d$ divides $n$. (Hint: notice that $(n+1)(n!+1) = (n+1)!+n+1$)
5
votes
5answers
887 views

Prove 24 divides $u^3-u$ for all odd natural numbers $u$

At our college, a professor told us to prove by a semi-formal demonstration (without complete induction): For every odd natural: $24\mid(u^3-u)$ He said that that example was taken from a high ...
4
votes
4answers
808 views

Proving that $ \gcd(a,b) = as + bt $, i.e., $ \gcd $ is a linear combination.

For any nonzero integers $ a $ and $ b $, there exist integers $ s $ and $ t $ such that $ \gcd(a,b) = as + bt $. Moreover, $ \gcd(a,b) $ is the smallest positive integer of the form $ as + bt $. I ...
3
votes
1answer
2k views

Prove the converse of Wilson's Theorem

... namely that if $n > 1$ and $(n − 1)!\equiv−1\pmod{n}$, then $n$ is prime. This is for a number theory class I'm in at Penn State. My idea is to follow accordingly, but I can't get it ...
2
votes
3answers
321 views

The number $n^4 + 4$ is never prime for $n>1$

I am taking a basic algebra course, and one of the proposed problems asks to prove that $n^4 + 4$ is never a prime number for $n>1$. I am able to prove it in some particular cases, but I am not ...
0
votes
1answer
184 views

Division rules for other number systems? [duplicate]

How could we make the same division rules for other number systems, like in our decimal system: a number is divisible with 2 if it's last digit is 0,2,4,6,8, by 3 if the sum of digits is divisible ...
0
votes
5answers
192 views

Proving that if $\;5\mid(a+11)\;$ and $\;5\mid(16-b),\;$ then $\;5\mid(a+b)$

Can you please help me a bit with this question? How do we show that $\;$ if $\;\;5\mid(a+11)\;$ and $\;5\mid(16-b),\;\;$ then $\;5\mid(a+b)\;$? Thanks a lot!
13
votes
2answers
305 views

Prove $6 \nmid [\left( \sqrt[3]{28} - 3 \right)^{-n}]$

Prove that: $$6 \not\left|\ \left\lfloor\frac 1 {(\sqrt[3]{28} - 3)^{n}}\right\rfloor \ (n \in Z^+)\right.$$ ($\lfloor x\rfloor$ = largest integer not exceeding $x$) I am very bad as English and ...
10
votes
3answers
763 views

How many 0's are in the end of this expansion?

How many $0's$ are in the end of: $$1^1 \cdot 2^2 \cdot 3^3 \cdot 4^4.... 99^{99}$$ The answer is supposed to be $1100$ but I have absolutely NO clue how to get there. Any advice?
12
votes
2answers
1k views

What is the remainder when $1! + 2! + 3! +\cdots+ 1000!$ is divided by $12$?

What is the remainder when $$1! + 2! + 3! +\cdots+ 1000!$$ is divided by $12$. I have tried to find the answer using the Binomial Theorem but that doesn't help. How will we do this? Please help.
7
votes
2answers
287 views

Prove Divisibility In Fibonacci Sequence Over A Prime Number

In The Fibonacci sequence which is defined as $$ F_n=F_{n-1}+F_{n-2}, $$ lets say we have the number $p$ which is an odd prime. Prove that: $F_{p-1} + F_{p+1} -1$ Is divisible by $p$. Prove that ...
11
votes
2answers
621 views

Does $n \mid 2^{2^n+1}+1$ imply $n \mid 2^{2^{2^n+1}+1}+1$?

There are two ways to try to prove this. One is in the title, the other is its de Morgan counterpart: $n \nmid 2^{2^{2^n+1}+1}+1 \implies n \nmid 2^{2^n+1}+1$. Disproving it requires only one example ...