-1
votes
1answer
30 views

Prove that L[f' ' ](s)$ = $sL[f](s)

Can anyone prove this question ? Let $f$:$\mathbb{R}$$→$$\mathbb{C}$ be continuous function such that $f$$(0)$ $=$ $0$ and that $f'$ be a piecewise continuous function and absolutely integrable on ...
0
votes
1answer
56 views

Using Convolution Theorem to find the Laplace transform

In previous questions I have used Laplace transform to find the inverse Laplace transform. I have worked through this work booklet ...
1
vote
1answer
65 views

Lower bounds of laplace transform of characteristic functions

I have the following integral: \begin{equation} f(\mu) = \int_0^\infty e^{-\mu t}\varphi_X(t)dt \end{equation} where $\varphi_X(t)$ is the characteristic function of some undetermined probability ...
1
vote
2answers
151 views

How to compute Inverse Laplace transform using Convolution

How do you evaluate the inverse transform below using convolution ? $$ \mathcal{ L^{-1} } \left[ {\frac{s}{(s^2 + a^2)^2}} \right] $$ I tried $$\begin{align} \mathcal{ L^{-1} } \left[ ...
1
vote
1answer
97 views

Convolution Laplace transform

Find the inverse Laplace transform of the giveb function by using the convolution theorem. $$F(x) = \frac{s}{(s+1)(s^2+4)}$$ If I use partial fractions I get: $$\frac{s+4}{5(s^2+4)} - ...
2
votes
1answer
110 views

Laplace transform having this unusual property in convolution?

Here is the problem Solve $y'(t) = 1 - \int_{0}^{t} y(t - v)e^{-2v}dv$ The solution sets $\mathcal{L}(y) = Y(s)$ and does the following Notice that in step 1, they have $$Y(s)\dfrac{1}{s+2}$$ ...
1
vote
1answer
353 views

a matrix inverse laplace transform problem

Let $\mathcal {L}^{-1}[\cdot]$ be an inverse Laplace transform. Let $A$ be a square matrix, and $I$ an identity matrix. Based on the fact that $\mathcal {L} ^{-1} [{(sI-A)}^{-1}] = e ^{tA}$, how can ...