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3
votes
6answers
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Proof By Contradiction, Rational Roots
This was an exam question that I got totally wrong and am a bit question.
Prove $x^3 + x + 1 = 0$ has no solutions. Prove by contradiction.
Assume: $x^3 +x +1 =0$ has at least one rational root.
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3
votes
4answers
223 views
Prove that if $(m - 1)! + 1$ is divisible by $m$, $m$ is a prime with $(m - 1)! = 1.2.3…(m - 2)(m - 1)$
$m$ is a positive integer, and $ m > 1$,
Prove that if $(m - 1)! + 1$ is divisible by $m$, $m$ is a prime.
Solve this by making a contradiction.
My english isn't so well.
Please help and thank you ...
2
votes
2answers
104 views
help me define the connectives for 3 value logic
so basically i have a project about 3 valued logic ie truth=1 false = 0, unknown = 1/2
in a previous project I had to come up with formulae for 2 valued logic as follows:
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