1
vote
2answers
86 views

How can I solve this problem without having to do it by hand?

I'm dealing with the following problem in computational programming. I'm trying to find a way to build an algorithm that can quickly resolve the following problem statement without forcing me to do it ...
0
votes
1answer
69 views

How can I solve this problem without doing it by hand? [duplicate]

I'm dealing with the following problem in computational programming. I'm trying to find a way to build an algorithm that can quickly resolve the following problem statement without forcing me to do it ...
1
vote
2answers
67 views

Is there any way to solve this problem without having to do it by hand? [duplicate]

I'm dealing with the following problem in computational programming. I'm trying to find a way to build an algorithm that can quickly resolve the following problem statement. Is there any way to group ...
2
votes
1answer
90 views

Sieve higher powers with logarithmic optimization

I am factoring number $N = 90283$ using quadratic sieve. Bound is $B = 44$. I find factor base to be $\{2, 3, 7, 17, 23, 29, 37, 41\}$. I have $50$ element sieving interval: $\{318, 921, 1526, ...
13
votes
1answer
1k views

Quadratic sieve algorithm

I am stuck with the sieving stage of Quadratic Sieve algorithm. I've read lots of papers to this point but I can't find any guidlines how to choose sieving interval or how sieving is actually done ...
3
votes
4answers
239 views

Prime factorization, Composite integers.

Describe how to find a prime factor of 1742399 using at most 441 integer divisions and one square root. So far I have only square rooted 1742399 to get 1319.9996. I have also tried to find a prime ...
4
votes
0answers
499 views

Obtain a contradiction

Motivation : The motivation is to show that the equation $x^{2b}.x^{2a} +(3-x^{2b}) x^{a} + (1-s^2)=0 $ has no solutions in integers for any values of $x,b,a,s$ ( choosen as per the constraints ...
1
vote
0answers
70 views

lower bounds for maximum computing times for integer factorisation

Supposing that n were known to have two prime factors, and that the computer had a database of all the primes $<\sqrt{n}$. Then, unless n is square, one factor would be $<\sqrt{n}$. If an ...
2
votes
1answer
95 views

Factoring short intervals

There are algorithms (e.g., SIQS) that factor individual numbers. For large ranges of numbers, sieving is more efficient: for example, $(x^2,x^2+x)$ can be factored in time roughly linear in $x$. ...