Boolean algebras are structures which behave similar to a power set with complement, intersection and union. Questions regarding Boolean algebras as structures, or regarding functions defined from/to Boolean algebras fit into this tag very nicely. For Boolean logic use the tag propositional logic

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help on simplifying boolean algebra

I need t show the the terms on the left simplify to the ones on the right $$(X+Y).(X'+Z)= X.Z+X'.Y$$ My attempt: I went with $$XX'+XZ+YX'+YZ= 0 +XZ+YX'+YZ$$ But I'm stumped beyond ...
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2answers
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Can$A \cap (B' \cap C')$ be $(A \cap B') \cap (A \cap C')$?

If I use the above statement, provided that it is right, in a question, would I have to prove it as well?
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1answer
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Algorithms - Finding Clique of size n in a Graph

I have the following statements (NOTE: $\bar x$ means the complement of $x$): $(x_1 V \bar x_2 V x_3) ∧ ( \bar x_1 V x_2 V x_3) ∧ (x_1 V \bar x_3) ∧ (x_2 V \bar x_3 V x_4)$ I need to do the ...
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1answer
830 views

Simplify the following expression using Boolean Algebra into sum-of-products (SOP) expressions

Simplify the following expression using Boolean Algebra into sum-of-products (SOP) expressions $Q.S.U + (Q' + S').(R + V) + U.(R + V) + Q' + S.T.U$ $.$ = AND $+$ = OR This is what I have so far ...
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Boolean functions

Boolean function f(x1,x2,x3): If f(x1,x2,x3)= TRUE then f(TRUE,x2,x3)= TRUE ...
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1answer
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Is this the correct way of drawing a combinatorial circuit based on the disjunctive normal form and logic table?

The logic table: $$\begin{array}{|c3:c|}\hline x & y & z & f(x,y,z) \\\hline 1 & 1 & 1 & 0 \\ 1 & 1 & 0 & 1 \\ 1 & 0 & 1 & 0 \\ 1 & 0 & 0 & ...
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Tests for combinational logic - product of sums simplification

I am trying to understand how to simplify the Boolean cover function $(4+6)(12+14)(0+1+2+3)(11)(3)(9)(13)(10+14)(1+3+9)$ which is a stuck-at fault test cover function derived in this paper. I know ...
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1answer
496 views

Minimize SOP and POS algebraically?

Is it possible to simplify an SOP (sum of products) or POS (product of sums) expression algebraically? I can only do it through k-maps. Example: $a'b'c'd' + a'b'c'd + a'b'cd' + a'b'cd + ab'c'd + ...
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29 views

Simplify a Boolean Algebra expression with don't cares

In my homework assignment, I'm asked to simplify an expression of Q'RS'T' + Q'R'S'T + RS'T with don't-cares of m3, m12, and m14. I know how I would achieve this result with a K-map, however the ...
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1answer
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Solving $n$-binary-variable system of equations using only combinations of $n \over 2$ variables when $n \over 2$ is even

It seems that it's impossible to find the unique solution to an $n$-binary-variable system of XOR equations if you only use all $(n \text{ choose } {n \over 2})$ equations combining half the ...
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1answer
35 views

necessity of $f(0)=0$ and $f(1)=1$ in homomorphisms of boolean algebras

Let $A,B$ be boolean algebras and let $f \colon A \rightarrow B$. $f$ is a homomorphism of boolean algebras if $f$ is a homomorphism of the corresponding lattices and $f(0)=0$ and $f(1)=1$. Why is it ...
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Boolean function analysis on random graphs?

Random graphs have some properties that are determined in some random way such as edge probabilities in the interval $[0,1]$. Ryan O'Donnell's book "Analysis of Boolean Functions" (2014) has analysis ...
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637 views

calculating number of boolean functions

I would just like to clarify if I am on the right track or not; I have these questions: Consider the Boolean functions $f(x,y,z)$ in three variables such that the table of values of $f$ contains ...
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number of permutation in a boolean expression containing only ANDs and ORs

I need to find the number of permutations of some expression which contains only conjunctions and disjunctions e.g.: $$ e = x_1x_2 \vee x_3x_4 $$ where $x_1x_2$ and $x_3x_4$ are boolean summands, ...
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9 views

Pseudo-Boolean functions restricted to integers

The Pseudo-Boolean functions are of the following form. $$ f : \mathbb{B}^n \to \mathbb{R} $$ I would like to know if there is a special sub-category of $$ f : \mathbb{B}^n \to \mathbb{Z} $$ with ...
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32 views

What will be the answer to this K-Map?

I have a K-Map and I need to figure out which expression isn't equivalent to the provided K-Map. ...
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1answer
55 views

Are all algebras groups?

It seemed to me that boolean algebra is a group because it is closed (You can't use boolean algebra and get a result that is outside the group) under a logical primitive(?) and order of operands and ...
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1answer
30 views

Boolean Algebra laws of deduction question

I have a question in which I'm a little stuck at answering, could anyone help? ...
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1answer
28 views

Want to check if my Boolean Algebra simplification is correct

$(A+B)(B+\bar B)(\bar B+C)$ Distributive LAW $(AB+A \bar B+B B+B \bar B)(\bar B+C)$ Distributive LAW $(A B \bar B+A B C+A \bar B \bar B+A \bar B C+B B \bar B+B B C+B \bar B \bar B+B \bar B C)$ ...
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finding essential prime implicants on k-map

I was given the K-map ab\cd 00 01 11 10 00.......1...0...0...0 01........1...0...0...1 11........0...0...1...0 10.......1...1....1....1 my prime implicants are ab',a'bd',acd,a'c'd',b'c'd' ...
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Quadratization of $5 x_1 x_2 − 7 x_1 x_2 x_3 x_4 + 2 x_1 x_2 x_3 x_5$ using Rosenberg's algorithm

In section 4.4 of Pseudo-Boolean Optimization by Boros et al., the authors have reproduced Rosenberg's quadratization algorithm as follows. Then they have given an example of implementing the ...
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1answer
30 views

Dependence of the derivative of a pseudo-Boolean function on its variables

I am going through Pseudo-Boolean optimization by Boros et al. In the section 2, the paper introduces the idea of derivative and residual of a peudo-Boolean function. It is claimed that both ...
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1answer
19 views

canonical expression in compact form??

Does canonical expression in compact form need to have all the variables in it? For example, if I have a,b,c, and d variables and the compact form comes out to be just c+d, is this possible? For ...
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quick question about writing consensus theorem

In order to prove $bc + abc + bcd + a'(d+c) = abc + a'c + a'd$ I got it down to $abc + a'c + a'd + bc + bcd$ (LHS), and from there I factor out $bc$ from $bc + bcd$, which is $bc(1+d)$, simplifies ...
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Memory and bits

If a memory's addressability is 64 bits. What does that tell you about the size of the memory address register (MAR) and memory data register (MDR)?
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Deriving minimal SOP forms from Karnaugh maps

Given the following picture, I have derived that the list of all prime implicants are a’c’d’, a’bd’, acd, ab’ and all essential prime implicants are also a’c’d’, a’bd’, acd, ab’. But I am not sure ...
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1answer
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Consensus Theorem and Boolean algebra

I am trying to prove the following boolean equality. $$bc + abc + bcd + a’(d+c) = abc + a’c + a’d$$ I have simplified the left side to $bc + a'd + a'c$ by factoring out a $bc(1)$. However, ...
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2answers
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self dual boolean function

How many self-dual Boolean functions of n variables are there?Please help me how to calculate such like problems. A Boolean function $f_1^D$ is said to be the dual of another Boolean function ...
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boolean algebra with finite elements

I need to define a boolean algebra with 8 elements. I know all the Axioms to define a binary boolean algebra but I don't know how to do that with 8 elements. Someone can guide me please? Thanks.
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1answer
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Boolean algebra - Maxterms

I have a boolean expression and I need to get to its canonical forms (sum of minterms and product of maxterms). In order to get an expression for the first canonical form, I need to multiply every ...
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2answers
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Boolean Logic using proofs

ABC' + C = AB + C I understand this using venn diagrams and intuition. However, I am not able to derive the proof for getting from one side to the other. It's probably very simple step that I keep ...
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Is there a name for a semiring in which both operations distribute over each other?

For a semiring over a set $S$, with the operations $+$ and $*$, along with respective units $0$ and $1$, we have the law: $(a + b) * c = (a * c) + (b * c)$ But there are some semirings in which the ...
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1answer
40 views

Demonstrate AB+C(A+B)=AB+C(A⊕B)

Please help me demonstrate that AB+C(A+B)=AB+C(A'B+AB'). I've tried a couple of times but i always reach AB=2AB .
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Ideal generated by a set of polynomials $X^{a/b}$ where each monomial having $a$ and not having $b$

Let $$\mathcal R=\mathbb Z_2[x_1,\dots,x_n]/\langle x_1^2-x_1,\dots,x_n^2-x_n\rangle.$$ I want to learn ideal arithmetics to deal with polynomials of the forms such as Consider a set of ...
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problem simplifying boolean algebra expression using consensus theorem

Please simplify this logic expression for me with helping boolean algebra : A'C'D + A'BD + BCD + ABC + ACD' I know that must use consensus theorem . my solve : STEP 1 : Terms 1 & 3 ...
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1answer
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Free product of the powerset algebras of group orbits. Interpretation

I am trying to interpretate the following sentence in the context of measures on groups and algebras, from J. Pawlikowski on "The Hahn-Banach theorem implies the Banach-Tarski paradox" Let $F$ be ...
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Quick question on Bitwise operations

I have some questions for homework to do with Bitwise operations, now it's a simple task but it doesn't actually explain how to handle the questions which is why I'm asking here before I begin ...
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2answers
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Simplify $AC'+A'C+BCD'=AC'+A'C+ABD'$

How to prove that $$AC'+A'C+BCD'=AC'+A'C+ABD'$$ approch: a way to demonstrate is expressed in its canonical form. Any hint would be appreciated.
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1answer
113 views

Existence of surjective homomorphism between Boolean algebras $\Lambda\subset\mathscr P(\mathscr B)\to\mathscr B$ (in ZF)

I am trying to prove the following theorem, due to Tarski according to W. A. J. Luxemburg on Reduced powers of the real number system and equivalents of the Hahn-Banach extension theorem: Given a ...
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How can I show a set B with 8 elements and two operations, such that the axioms of huntington for boolean algebra holds?

If It was about two members I would have choose B={0,1} with the operations: AND , OR And prove this. But how can I do this with 8 elements?
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4answers
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Boolean algebra; what does <-> mean?

Expression :$$(p\rightarrow q)\leftrightarrow(\neg q\rightarrow \neg p)$$ What does the symbol $\leftrightarrow$ mean ? Please explain by drawing the truth table for this expression and also with ...
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1answer
84 views

Simplifying a Boolean expression for two-level NAND gate circuits

The expression is: F = (X' + Y' + Z')(Y' + A') I have no clear idea on how to go about simplifying this with Boolean algebra. After it's simplified, I'll need to implement it only using NAND gates. ...
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1answer
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Boolean functions that are not too far from all linear functions.

Suppose I have a Boolean function $ f:\mathbb{F}_2^n\rightarrow \mathbb{F}_2 $ which satisfies the following property: $$d(f, \ell)\leq 2^{n-1}\quad\forall\; \text{linear functions}\; \ell .$$ where ...
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1answer
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Boolean Simplification $ABC' + BC'D' + BC + C'D$

I'd like to simplify this equation: $ABC' + BC'D' + BC + C'D$ prove it to $B + C'D$ My attempt is : $$\begin{align} &= ABC' + BC'D'(A+A') + BC + C'D\\ &= ABC' + ABC'D' + A'BC'D' + BC + C'D\\ ...
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1answer
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Boolean expression explanation

Could someone explain how to get the following Boolean expression in its simplest form, I am having difficulties working it out step by step $$A+B+A*B$$
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1answer
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Boolean functions- depth of generated function and info

I'm looking for a general book/link to information about boolean function (Function from to {0,1}), we've introduced them in a logic course but it seems we won't focus on them.
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Boolean Algebra - Prove XYZ + XYZ' + XY'Z + X'YZ = XY + XZ + YZ

Trying to prove $((X\land Y\land Z)\lor (X\land Y\land \lnot Z)\lor (X\land \lnot Y\land Z ) \lor (\lnot X\land Y\land Z)) \equiv ((X\land Y)\lor (X\land Z)\lor (Y\land Z))$ and I am a bit stuck. I ...
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A logic circuit simplification and boolean algebra question

Here is my logic circuit Hey guys, I have a question that I'm working on for 2 days but I couldnt find a way out. The question is : Determine a boolean function F(x,y,z) and reduce F using boolean ...
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Boolean Algebra - Xor simplification

I have a boolean equation: $e(g \oplus (g + b))$ and it is simplified to $e(\lnot g)b$. I do not see how this simplification is done. What i did was the following: $e(g \oplus (g + b)) --> ...