Coefficients involved in the Binomial Theorem. $\binom{n}{k}$ counts the subsets of size $k$ of a set of size $n$.

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Binomial coefficient sum over top index

I am trying to evaluate a sum over binomial coefficients which is giving me some problems. Specifically I want to calculate: $$\sum_{r=0}^{c-1}\binom{r+n}{n}\frac{1}{c-r}$$ My main thought was to ...
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4answers
77 views

Is $\sum^{n-1}_{k=1}{n\choose k}x^{n-k}y^k$ always even?

Is $$ f(n,x,y)=\sum^{n-1}_{k=1}{n\choose k}x^{n-k}y^k,\qquad\qquad\forall~n>0~\text{and}~x,y\in\mathbb{Z}$$ always divisible by $2$?
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2answers
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Binomial coefficient series

I'm practicing for my maths term test mainly on binomial coefficients. I can't seem to find out how to prove the following identity. Any advice? $$ \sum\limits_{k=1}^n (-1)^{k+1} k{{n}\choose k} = 0 ...
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3answers
52 views

Proving $\sum_{m=0}^M \binom{m+k}{k} = \binom{k+M+1}{k+1}$

Prove that $$\sum_{m=0}^M \binom{m+k}{k} = \binom{k+M+1}{k+1}$$ by computing the coefficient of $z^M$ in the identity $$(1 + z + z^2 + \cdots ) \cdot \frac{1}{(1-z)^{k+1}} = \frac1{(1-z)^{k+2}}.$$ I ...
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+50

On a sum related to alternating sign matrices

I'm trying to prove that $$A_{n,k} = \binom{n+k-2}{k-1}\frac{(2n-k-1)!}{(n-k)!}\prod_{j=0}^{n-2}\frac{(3j+1)!}{(n+j)!}$$ implies $$A_n = \sum_{k=1}^nA_{n,k}=\prod_{j=0}^{n-1}\frac{(3j+1)!}{(n+j)!}.$$ ...
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1answer
32 views

Binomial sum of derivatives

I would like to know the result of the following sum: $$\sum_{p=0}^m \binom{m}{p}(-1)^{p-1}\frac{\partial^{p-1}}{\partial x^{p-1}}f(x)\cdot(-1)^{m-p-1}\frac{\partial^{m-p-1}}{\partial ...
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1answer
39 views

An equality involving binomial coefitients

I am wondering why formula $$\sum_{j=k}^n\binom{n}{j}(-1)^j = (-1)^k\binom{n-1}{k-1} $$ is correct only for $1<k<n+1$. Could it be extended to $0<k<n+1$? I found this formula here.
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6answers
129 views

A limit on binomial coefficients

Let $$x_n=\frac{1}{n^2}\sum_{k=0}^n \ln\left(n\atop k\right).$$ Find the limit of $x_n$. What I can do is just use Stolz formula. But I could not proceed.
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2answers
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Some algebraic inequalities with the binomial theorem.

I am working on proving the following limits. 1), $\lim_{n \to \infty} \sqrt[n]{n} = 1$ 2), If $p >0$ and $\alpha \in \Bbb R$, then $\lim_{n \to \infty} {n^{\alpha}\over{(1+p)^n}} =0$ ...
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1answer
39 views

What is the function given by $\sum_{n=0}^\infty \binom{b+2n}{b+n} x^n$, where $b\ge 0$, $|x| <1$

For a nonnegative integer $b$, and $|x|<1$, what is the function given by the power series $$ \sum_{n=0}^\infty \binom{b+2n}{b+n} x^n. $$ For $b=0$, this post shows $$ \sum_{n=0}^\infty ...
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2answers
132 views

What's the intuition behind this equality involving combinatorics? [duplicate]

What is the intuition behind $$ \binom{n}{k} = \binom{n - 1}{k - 1} + \binom{n - 1}{k} $$ ? I can't grasp why picking a group of $k$ out of $n$ bijects to first picking a group of $k-1$ out of $n-1$ ...
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2answers
52 views

Binomial Coefficients Combinatorics

For a positive integers n, prove that $$\displaystyle\sum\limits_{v=0}^n \frac{(2n)!}{(v!)^2 ((n-v)!)^2} = \binom{2n}{n}^2.$$ If somebody could please help me with this question, I would greatly ...
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1answer
32 views

How to maximize $n!\sum^n_{k = 0}\frac{a^k(1+(-1)^{n-k})}{k!(n-k)!} \pmod{a^2}$ for a given $a$?

Short Version of the Question: How do I maximize the value of $n!\sum^n_{k = 0}\frac{a^k(1+(-1)^{n-k})}{k!(n-k)!} \pmod{a^2}$ for a given $a$? Long Version of the Question: I'm currently attempting ...
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1answer
59 views

Sum of binomial probabilities

One of my friends is building a game where the player will get questions from 6 different categories. Each category has a total of 50 questions. A single game consists of answering one question from ...
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3answers
69 views

A binomial identity from Mathematical Reflections

Here is the problem: Let $m,n$ be positive integers with $n>m$. Prove that $\displaystyle\sum_{k=0}^{n} (-1)^{k}\binom{n}{k}\binom{m+n-2k}{n-1}=\binom{n}{m+1}$ This problem is O243 of ...
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2answers
29 views

Distribution of $n$ balls to 10 cells; Inclusion-exclusion problem

So I got another ( :[ ) problem I got stuck with. So before I get going with that, I would like to know if you know any places where I can learn the principles of these subjects (compositions, ...
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3answers
32 views

Proof that $\sum_{k=0}^m \binom{m}{k}\frac{1}{k+1} = \frac{2^{m+1}-1}{m+1}$ [duplicate]

Recently I needed to compute $E[\frac{1}{X+1}]$ where $X\sim Bin(m, \frac 1 2)$. While expanding, I came across the sum $\sum_{k=0}^m \binom{m}{k}\frac{1}{k+1}$, which I was unable to solve. Plugging ...
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2answers
82 views

Proof of the identity $2^n = \sum\limits_{k=0}^n 2^{-k} \binom{n+k}{k}$

I just found this identity but without any proof, could you just give me an hint how I could prove it? $$2^n = \sum\limits_{k=0}^n 2^{-k} \cdot \binom{n+k}{k}$$ I know that $$2^n = ...
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3answers
84 views

Counting the numbers between $1$ and $1,000,000$ whose digits sum to $30$

What's the number of numbers between $1$ and $1,000,000$ whose digits sum is $30$? So I thought of this as a stars and sticks problem, so in the case you have $35\choose 5$ numbers whose sum is ...
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3answers
142 views

Combinatorial proof of $\sum^{n}_{i=1}\binom{n}{i}i=n2^{n-1}$.

Prove $$\sum^{n}_{i=1}\binom{n}{i}i=n2^{n-1}$$ I can't find counting interpretations for either of the sides. A hint of "if $S$ is a subset of $\{1, . . . , n\}$ and $S^\prime$ is its complement ...
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2answers
58 views

Binomial probability with summation

Show that $$\sum_{k=0}^{m} \frac{m!(n-k)!}{n!(m-k)!} = \frac{n+1}{n-m+1}$$ Attempt: It becomes: $$\sum_{k=0}^{m } \frac{\binom{m}{k}}{\binom{n}{k}}$$ Telescoping, pairing, binomial theorem don't ...
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3answers
132 views

Evaluate a sum with binomial coefficients

$$\text{Find} \ \ \sum_{k=0}^{n} (-1)^k k \binom{n}{k}^2$$ I expanded the binomial coefficients within the sum and got $$\binom{n}{0}^2 + \binom{n}{1}^2 + \binom{n}{2}^2 + \dots + \binom{n}{n}^2$$ ...
8
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2answers
119 views

A sum with binomial coefficients

Show that $$\sum_{k=0}^{n}(-1)^k\binom{n}{k}(n-2k)^{n+2}=\frac{2^{n}n(n+2)!}{6}.$$
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3answers
67 views

Factorial Equality Problem

I'm stuck on this problem, any help would be appreciated. Find all $n \in \mathbb{Z}$ which satisfy the following equation: $${12 \choose n} = \binom{12}{n-2}$$ I have tried to put each of them ...
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25 views

Binomial Expansion problem error

I tried solving this question but failed. a) Expand $(1+2x)^{1/4}$ in ascending powers of $x$ up to and including the term in $x^3$, simplifying each term as far as possible. b) By substituting ...
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1answer
42 views

Binomial theorem for prime exponent

Could you explain to me why for prime $p$ we have the following? $$(x+y)^p - (x^p + y^p)= x^p + \binom{p}{1}x^{p-1}y + \binom{p}{2}x^{p-2}y^2 + \binom{p}{p-1}xy^{p-1} + y^p.$$ I found it here: ...
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0answers
84 views

Prime numbers with binomial coefficients

Let $p$ be an odd prime and $n$ a positive integer. Prove that $p+1$ divides $n$ if and only if $$\sum_{k\equiv j\pmod{p-1}}^n^{}\binom{n}{k}(-1)^{\frac{(k-j)}{p-1}}\equiv 0 \mod p$$ for every $$j\in ...
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1answer
50 views

Prime numbers with binomial coefficients

Question: Prove that for any prime $p>3$, the number $\binom{2p-1}{p-1}-1$ is divisible by $p^{3}$. Attempt: Since every integer that is relatively prime to p has a multiplicative inverse modulo ...
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2answers
37 views

Prove that a sum converges to a trigonometric expression

$$2^n \cos \left (\frac{n \pi}{2} \right )=\sum_{k=0}^{n} (-1)^k \binom{2n}{2k}$$ I expanded the LHS and got $$\binom{2n}{0}-\binom{2n}{2}+\binom{2n}{4}-\binom{2n}{6}+\cdots+(-1)^{n}\binom{2n}{2n}$$ ...
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1answer
36 views

When are the binomial coefficients equal to a generalization involving the Gamma function?

Let $\Gamma$ be the Gamma function and abbreviate $x!:=\Gamma(x+1)$, $x>-1$. For $\alpha>0$ lets generalize the binomial coefficients in the following way: $\binom{n+m}{n}_\alpha:=\frac{(\alpha ...
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0answers
27 views

Sum involving binomial cofficients [duplicate]

I want to Solve a binomial Series of type : aC0*bCd + aC1*bc(d-1) -----------------(aC(k-1))*(bCd-(k-1)) Can anyone please suggest on how to reduce such series? ...
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1answer
30 views

$\frac{1}{4^n}\binom{1/2}{n} \stackrel{?}{=} \frac{1}{1+2n}\binom{n+1/2}{2n}$ - An identity for fractional binomial coefficients

In trying to write an answer to this question: calculate the roots of $z = 1 + z^{1/2}$ using Lagrange expansion I have come across the identity $$ \frac{1}{4^n}\binom{1/2}{n} = ...
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1answer
34 views

Summing ratio of partial sums of binomial coefficients

I would like to approximate the following when $n \gg k$. $\sum_{y = k + 1}^n \frac{\sum_{m = 0}^{k - 1} {y - 2 \choose m} (y - 1)}{\sum_{m = 0}^k {y - 1 \choose m}}.$ The formula can be re-written ...
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1answer
43 views

Weighted sum of ratio of partial sum of binomial coefficients

I would like to approximate the following sum when $n \rightarrow \infty$ and $n \gg k$, $$\sum_{x = k}^n \sum_{y > x}^n \frac{\sum_{m = 0}^{k - 1} {y - 2 \choose m}}{\sum_{m = 0}^k {y - 1 \choose ...
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3answers
57 views

Show that ${-n \choose i} = (-1)^i{n+i-1 \choose i} $

Show that ${-n \choose i} = (-1)^i{n+i-1 \choose i} $. This is a homework exercise I have to make and I just cant get started on it. The problem lies with the $-n$. Using the definition I get: $${-n ...
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2answers
28 views

standard deviation of a certain distribution

If I have a list of N outcomes of drawing a number from the set {-1\$,+1\$}, and I know that the probability of getting (in a single draw) (-1\$) is p, and probability of getting (in a single draw) ...
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1answer
70 views

Sum of product of binomial coefficients $ = (-1)^n$

Based on the binomial expansion of $(1+x)^n$, show that: $$\sum_{k=0}^{n}(-1)^k\binom{n}{k}\binom{n + k}{k} = (-1)^n$$ This is a question from a very old high school exam paper I came across. It ...
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1answer
54 views

Expected number of edges: does $\sum\limits_{k=1}^m k \binom{m}{k} p^k (1-p)^{m-k} = mp$

Find the expected number of edges in $G \in \mathcal G(n,p)$. Method $1$: Let $\binom{n}{2} = m$. The probability that any set of edges $|X| = k$ is the set of edges in $G$ is $p^k (1-p)^{m-k}$. ...
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2answers
71 views

Looking for combinatorial identity: $\sum\limits_{j=0}^k{n \choose k-j}{m \choose j}$ [duplicate]

Is there a nicer closed form expression for the following expression? $$\sum_{j=0}^k{n \choose k-j}{m \choose j}$$
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1answer
37 views

Help with a question on binomial

Prove that $$\sum_{r=1}^{k}(-3)^{r-1}\dbinom{3n}{2r-1}= 0,$$ where $k=\frac{3n}{2}$, and $n$ is an even positive integer
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1answer
69 views

A combinatorial identity

Let $m$ be a positive integer. I have trouble proving that $$\sum_{k=0}^m (-1)^k 2^{2k-1}\left[{m+k-1\choose 2k}+{m+k\choose 2k}\right]=(-1)^m$$ Anyone?
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1answer
55 views

How to prove the identity $(n-k)! \sum _{i=0}^{n-k} \frac{(k+i-1)!}{i!} = \frac{n!}{k}$?

I am stuck in proving the following : $$(n-k)! \sum _{i=0}^{n-k} \frac{(k+i-1)!}{i!} = \frac{n!}{k}$$ NOTE: I don't want any combinatorial proof. I think it is some algebraic manipulation.
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3answers
110 views

combinatorial argument and by induction proof

Let n be a fixed natural number. Show that: $$\sum_{r=0}^m \binom {n+r-1}r = \binom {n+m}{m}$$ (A): using a combinatorial argument and (B): by induction on $m$?
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2answers
38 views

Identity of binomial series with factorial.

I'm looking for a simple identity for the formula: $$ \sum_{k = 0}^{p} \binom{p}{k} \cdot k! \cdot x^k $$ In words, I have $p$ "players" who can choose to play or not (every player is represented by ...
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1answer
65 views

Is this binomial coefficient identity already known?

$ \sum_{k=r}^{n} {n \choose k} = \sum_{k = r - 1}^{n-1}{k \choose r -1}2^{n-1-k} $ The proof is trivial but I haven't seen this identity anywhere. Perhaps it's a special case of a more general ...
9
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4answers
149 views

Binomial Theorem Identities

What's the actual difference between these two formulas (they're both in the chapter regarding binomial theorem). They're from two different textbooks : $${n\choose k}+{n\choose k+1}={n+1\choose ...
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3answers
85 views

Distributing identical objects to identical boxes

We have 6 identical things to be distributed in 4 identical boxes such that empty boxes are allowed the find the number of ways to distribute the things ?
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2answers
54 views

Sum of square binomial coefficients [duplicate]

Please feel free to close this is necessary as I didn't see exactly this question (some variations that I tried but didn't seem to apply. Prove: $$\sum_{k=0}^{n}{\binom{n}{k}^2}=\binom{2n}{n}$$ I ...
10
votes
2answers
180 views

Asymptotics of the sum of squares of binomial coefficients

We are trying to estimate the cardinality $K(n,p)$ of so-called Kuratowski monoid with $p$ positive and $n$ negative linearly ordered idempotent generators. In particular, we are interesting in the ...
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2answers
52 views

Combinatorial Proof of Binomial Coefficient Identity [duplicate]

Consider the sum $\displaystyle\sum_{j=r}^{n+r-k} \binom{j-1}{r-1}\binom{n-j}{k-r} = \binom{n}{k}$ I am looking to show this identity combinatorially. Is the general idea perhaps to remove j from n ...

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