# Trigonometrical functions

I've been trying to solve this for 1hour, but I can't do it. I don't know if I'm missing something or it just doesn't open to me...

Simplify the following expression:

$$\frac{\sin^2 x - \cos^2 x}{ \sin x - \cos x}$$

Help will be appreciated.

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Factor the numerator ($a^2-b^2=(a+b)(a-b)$). –  David Mitra Jan 17 '12 at 22:51
Thank You, now it seems so obvious. I don't know what I was thinking. –  JanL Jan 17 '12 at 23:01
Your welcome; glad to help. –  David Mitra Jan 17 '12 at 23:07

It's $\sin(x)+\cos(x)$. Follow Mitra's hint!
It might further be simplified to $\sqrt{2}\sin(x + \pi/4)$.