Take the 2-minute tour ×
Mathematics Stack Exchange is a question and answer site for people studying math at any level and professionals in related fields. It's 100% free, no registration required.

then the question is,the larger radius D,the small radius d,get the largest number of small circle put in the larger?

share|improve this question
5  
See this and this. –  Guess who it is. Jan 5 '12 at 10:39
2  
See also Circle packing in a circle. –  lhf Jan 5 '12 at 15:09
1  
I believe this is still an open problem. –  Rogelio Molina Apr 24 at 5:52

2 Answers 2

The answer can be closely approximated by this equation:

Number of Circles $= 0.83\frac{R_2^2}{r_1^2} - 1.9$ (rounded down to whole number)

where: $R_2$ = radius of larger circle $r_1$ = radius of smaller circle

share|improve this answer
    
I made some edits to the typesetting. Please check that I've left the meaning the same. –  Simon Hayward Dec 17 '12 at 14:53
4  
I'm skeptical of the result particularly for $R\gg r$; at that point you should be able to get arbitrarily close to the $\pi/\sqrt{12}\approx 0.9$ density of the full planar packing, minus some boundary effects that can't be any larger than $O(\frac{R}{r})$. –  Steven Stadnicki May 3 '13 at 22:13

infinite, since the thickness cannot be computed because the fraction answer in infinite

share|improve this answer
    
I suspect the question is asking for the case when all the circles are of equal radius, in which case it is always finite (but for arbitrarily small radius, arbitrarily many circles may fit) –  Milo Brandt Dec 13 '14 at 19:12

Your Answer

 
discard

By posting your answer, you agree to the privacy policy and terms of service.

Not the answer you're looking for? Browse other questions tagged or ask your own question.