Take the 2-minute tour ×
Mathematics Stack Exchange is a question and answer site for people studying math at any level and professionals in related fields. It's 100% free, no registration required.

I don't understand a question from a Math exercise. I did many things asked before, but I found this part very difficult to understand:

What is the percentage ratio between the combined area of six cylinder bottoms and the area of box bottom in case A?

I just calculated the area of the box (which is a rectangle): 66*396 = 26136. And about the cylinders, we know that h=187 mm and r=33 mm...

Maybe is a problem of my bad English, but I can't answer to the above question. Could you bring me some light?

Thank you very much in advance!

share|improve this question

1 Answer 1

The cylinders seem to have a circular cross section of radius 33 mm, so the area of the bottom of one is $\pi (33\ \mathrm{mm})^2$. Six will just fit in a row in a rectangle $66\ \mathrm{mm} \times 396\ \mathrm{mm}$, whose area you have calculated. So it is $\frac{6 \pi 33^2}{66\times396}$ which should be the same as the ratio between a circle and the circumscribed square (why?).

share|improve this answer
    
@Rahul Narain: Thanks. –  Ross Millikan Dec 28 '11 at 4:32

Your Answer

 
discard

By posting your answer, you agree to the privacy policy and terms of service.

Not the answer you're looking for? Browse other questions tagged or ask your own question.