# Why is there a 1/6 chance of rolling a “6” after I have just rolled a “6”? [duplicate]

Possible Duplicate:
What are the odd of a single coin toss after many consecutive ones?

If I have a fair dice and I rolled a six 5 times in a row, it would appear to me that the next row have a lesser chance of being a six.

However the laws of probability state that the next row would still have a 1/6 chance of being a six (and not being lower, despite the number of times six had just appeared).

This seems very counter-intuitive. I was wondering what's a good analogy / explanation to understand this phenomenon ?

-
See independence, and see here for the same question only about coins. –  Zev Chonoles Dec 13 '11 at 16:57
Successive dice rolls (of a fair die) are independent events. –  user5137 Dec 13 '11 at 16:58
Suppose you walk into a room in which someone had been throwing a die. You walk in just as he makes a roll. What is the probability he throws "6"? Would it matter what he had rolled before? –  David Mitra Dec 13 '11 at 16:59
the laws of probability state that the next row... The laws of physics, I'd rather say. In our physical model of things (dice), the outcome of a "good" die only depend on physical processes that can be very complex, but which should not depend on past outcomes: the die does not have any property that makes it remember its past, does it? –  leonbloy Dec 13 '11 at 17:00