How many permutations can happen if none of the boys stand next to each other?
Hint - perhaps it is 28800 but not quite sure.
Simpler question - calculate number of permutations when girls stand in front of boys. I think it will be 5!x5! = 14400
For the first part, will I be able to use provided solution for the following task? Black, red and white balls. There is nine of them. Find number of permutations if the same colored balls are not beside each other?