# Showing that $\int \liminf_{n \to \infty} f_{n}(x) dx \le \liminf_{n \to \infty} \int f_{n}(x) dx$

I don't know why, but I find this problem counter intuitive to me.

Prove that if $\{f_n\}$ is a sequence of measurable nonnegative functions on a measurable set $E$ and $f(x)=\liminf_{n \to \infty} f_{n}(x)$, then

$$\int_{E} f(x) dx \le \liminf_{n \to \infty} \int_{E} f_{n}(x) dx.$$

Can someone outline the proof for me please?

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Fatou's lemma - proof is givein in Wikipedia's article: en.wikipedia.org/wiki/… – Martin Sleziak Dec 7 '11 at 16:31
haha, how stupid i am. Thx. – Alex J. Dec 7 '11 at 16:41
Alex, maybe you'd care to type up an answer...? – The Chaz 2.0 Dec 7 '11 at 17:20

For me, the key point is the definition of $\liminf$.