# Prove: a countable intersection of open and dense sets in a compact Hausdorff $X$ is dense

Let $X$ be a compact Hausdorff space and let $\{U_n\}$ be a countable collection of subsets that are open and dense in $X$. Show that the intersection $$\bigcap\limits_{n=1}^\infty U_n$$ is dense.

I tried to show that the closure of this intersection is equal to the intersection of the closures of each set, but I'm not getting anywhere.

Any help would be greatly appreciated.

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This makes two questions in the last hour for which the answer is "Actually, this is the Baire Category Theorem..." Coincidence? – Pete L. Clark Dec 6 '11 at 4:13
Could "Student" be Baire himself looking for approval? – mathmath8128 Dec 6 '11 at 5:20
@aengle: ...and here I always thought that Student's actual surname was "Gosset"... :D – J. M. Dec 6 '11 at 9:55

What you are looking for is Baire's theorem. (The proof on Wikipedia is for a complete metric space, but the proof is similar for a compact Hausdorff space.)

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Let $X$ be a compact and Hausdorff space.

Let $\{U_n\}$ be a countable collection of subsets that are open and dense in X.

Let $O$ be an open set. Since $U_1$ is dense, it must intersect $U_1$ in a non-empty open set $O_1$. Let $x_1 \in O_1$ , and since the space is Hausdorff and compact exists $B_1(x_1)$ a open set that contains $x_1$ and $\overline{B_{1}(x_1)}$ is contained in $O_1$. Now, because $U_2$ is dense, intersects $B_{1}(x_1)$ in a non-empty open set $O_2$. In the same way, let $x_2 \in O_2$ , and take $B_2(x_2)$ such that the closure $\overline{B_{2}(x_2)}$ is contained in $O_2$.

With this process we obtained a nested sequence of non-empty closed sets $\overline{B_1} \supseteq \overline{B_2} \supseteq \overline{B_3} \supseteq ... \supseteq \overline{B_n} \supseteq ...$ . As $X$ is compact, then exists $x \in \bigcap\limits_{n=1}^{\infty} \overline{B_n}$. In this way, $x \in O_n$, for each $n$ and hence $x \in O \cap \bigcap\limits_{n=1}^{\infty} {U_n}$. Thus $\bigcap\limits_{n=1}^{\infty} {U_n}$ intersects each non-empty set $O$ in a least one point, that is precisely, that $\bigcap\limits_{n=1}^{\infty} {U_n}$ is dense in $X$.

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While this link may answer the question, you should include the essential parts of the answer here. – N. F. Taussig Feb 22 at 15:06
Thank you, I already did. – Astrid A. Olave H. Feb 22 at 21:23