I'm failing to understand how to come to the answer to this question.
If you roll a fair die six times, what is the probability that the numbers recorded are $1$, $2$, $3$, $4$, $5$, and $6$ in any order?
The answer given is $6!(1/6)^6 = 3/324$
Can anyone explain to me how to get to that answer? I would really appreciate the help! :)