I will try to answer somewhat without giving it away.
For A, try and actually do the integration. Do you run into any trouble? If so, can you explain what the problem is? (Depending on context, i.e. if you include complex valued functions as integrable in your definition, then you may have no problem.)
For B, the comments left by T.Bongers give good indication what the answer is. In performing the integration, the discontinuity does not effect the answer. This holds more generally for any function with a countable number of discontinuities.
For C it is important to know what the definition of integration is. When this is used in the context of Riemann integration, often the only sets allowed in the integration are compact (i.e. intervals [a,b]). If this is the case, C is true (this should have been a fundamental concept from Calculus). If unbounded domains are also allowed, your counterexample makes sense.
For D I would appeal to a well-known theorem in Real Analysis which states that a bounded function $f$ on a compact interval $[a,b]$ is Riemann integrable if and only if its set of discontinuities has measure zero (for instance, they are countable). Therefore, creating a bounded function with a set of discontinuities which do not have measure zero is a counterexample to this statement.
It seems like you are reviewing integrability conditions (based on your other recent question), but you need to have a precise definition of integrability in hand and some familiarity with the standard theorems (i.e. those for C and D that I have used aboved). There are different notions of integrability, but from the other questions you have mentioned I have assumed you meant Riemann integrable. I would return to the definition you are working with, and see if it implicitly assumes that the function is being integrated over an interval $[a,b]$.