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Hi would would I go around to solve the following, there is no other information stat is given other than the fact that i have already expanded this from this



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Have you tried expanding the left side of the first equation? – mb7744 Jun 16 '14 at 23:34
Note that since $(25-y)(x+8)=200+25x-8y-xy$ we get $xy=0$. – André Nicolas Jun 16 '14 at 23:40

Hint: You can rewrite the second equation as $y=\frac 18(25x-323)$, substitute that into the first and you will have a quadratic equation. It will give you two values for $x$, which you can plug into the second to find $y$.

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