Take the 2-minute tour ×
Mathematics Stack Exchange is a question and answer site for people studying math at any level and professionals in related fields. It's 100% free, no registration required.

If I have a particularly nice space $X$ (Hausdorf, locally path connected, semi-locally 1-connected, I think), then then there is an equivalence of categories between the cover category over $X$ and the groupoid cover category over the fundamental groupoid $\pi X$. One direction of this equivalence is given by the fundamental groupoid functor. The other is given by 'lifting' a groupoid cover $B \rightarrow \pi X$ to a topological cover $B_! \rightarrow X$. What is the topology on $B_!$?

I am traveling and left my copy of Topology and Groupoids at home.

share|improve this question
1  
Do you understand the "classic" pointed case? I.e. the equivalence between covers of $X$ and $\pi_1(X,x)$-sets (when $X$ is also path-connected). –  Martin Brandenburg Jun 8 at 17:31

1 Answer 1

up vote 3 down vote accepted

Given a space $X$ and covering morphism of groupoids $q: G \to \pi_1 X$ the aim is to construct a topology on $Y= Ob(G)$ so that $p=Ob(q): Y \to X$ is a covering map of the kind required. Given a point $x \in X$ one assumes one can choose a neighbourhood $N$ of $x$ such that the induced map of groupoids $\pi_1(N) \to \pi_1(X)$ lifts to a set of morphisms $\pi_1(N) \to G$ such that these map $x \in N$ to all points $y$ in $q^{-1}(x)$. For this one needs that the image of $\pi_1(N,x)$ in $\pi_1(X,x)$ is contained in the images under $p$ of all $G(y)$. This gives one the necessary local condition. Assuming this, the image under these lifts of $N$ in $Y$ gives a basis for the topology of $Y$ which is needed. This is the account in Topology and Groupoids, as it was in the 1968, 1988 editions.

To my mind, the advantage of this approach is that we compare lifting maps with lifting morphisms, while the so-called classic approach uses actions (of groups) which are another step away from the direct analogy between maps and morphisms. Chacun a son gout!

A correction to the book is that the Hausdorff condition is not needed for covering space theory!

A generalisation to "semicoverings" is given by Brazas.

I gave in Paris on June 5, 2014, a talk which is available on my preprint page, explaining how the use of groupoids in this area led me and colleagues to "higher groupoids" in algebraic topology!

share|improve this answer

Your Answer

 
discard

By posting your answer, you agree to the privacy policy and terms of service.

Not the answer you're looking for? Browse other questions tagged or ask your own question.