Mathematics Stack Exchange is a question and answer site for people studying math at any level and professionals in related fields. Join them; it only takes a minute:

Sign up
Here's how it works:
  1. Anybody can ask a question
  2. Anybody can answer
  3. The best answers are voted up and rise to the top

Is this true that any finite word of the alphabet $\mathcal{A_9}=\{0,1,2, \ldots,8,9\}$ appears somewhere in the decimal representation of $\sqrt{2}$ ?

Thanks !

share|cite|improve this question
up vote 6 down vote accepted

What you are trying to ask is if $\sqrt{2}$ is a normal number. But while it is widely believed to be so, a proof has yet to be found.

Fun fact: Same goes for $\pi$, and that if true, everything in the universe can be expressed in the decimal digits of $\pi$ or $\sqrt{2}$.

share|cite|improve this answer
Sorry, I guess I was writing as you had finished posting; I may end up deleting my post. – user99680 Jun 6 '14 at 2:18
Saying that $\sqrt 2$ is normal is a much stronger claim than what the8thone is asking about, though it's a very similar proposition. – user2357112 Jun 6 '14 at 3:23

Your question is the same, or close to, the question of whether $\sqrt 2$ is normal : This is still open.

share|cite|improve this answer
No problem! Keep it and receive a +1. – BlackAdder Jun 6 '14 at 2:27
Thanks, BlackAdder. – user99680 Jun 6 '14 at 2:28

Your Answer


By posting your answer, you agree to the privacy policy and terms of service.

Not the answer you're looking for? Browse other questions tagged or ask your own question.