I can't believe the alternative method I just saw to calculate the average of two numbers:
I use the following: (a+b)/2 = avrg(a,b) (b+a)/2 = avrg(a,b) Found someone using this: a+((b-a)/2) = avrg(a,b) b+((a-b)/2) = avrg(a,b)
How to calculate
avrg(a,b,c) using the second method? (e.g for the first one is
How can I transform the first one into the second one, or otherwise find some proof they both are equally equal?