# A doubt on indefinite integral [closed]

Find indefinite integral of $f(x) = 9x^3\sqrt{x} - 2x^5 +e^{-2x} + 11x$

Here is my attempt: $$\int\left(9x^3\sqrt{x} - 2x^5 +e^{-2x} + 11x\right)\ dx\\ =9\int x^{7/2}\ dx -2\int x^5\ dx + \int \frac{x}{e^2}\ dx+11\int x\ dx$$ (9 x^(7/2)-2 x^5+x/e^2+11 x) dx

= 9 ∫ x^(7/2) dx-2 ∫ x^5 dx+(11+1/e^2) ∫ x dx

= 2 x^(9/2)-2 ∫ x^5 dx+(11+1/e^2) ∫ x dx

= 2 x^(9/2)-2 ∫ x^5 dx+1/2 (11+1/e^2) x^2

= 2 x^(9/2)-x^6/3+1/2 (11+1/e^2) x^2+constant

= (x^2 (e^2 (12 x^(5/2)-2 x^4+33)+3))/(6 e^2)+constant

I have done this for ten times and this is what I got. Is it looking right? Any help please.

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## closed as unclear what you're asking by heropup, Mike, John, J. W. Perry, user91500Jun 2 at 4:40

Please clarify your specific problem or add additional details to highlight exactly what you need. As it's currently written, it’s hard to tell exactly what you're asking. See the How to Ask page for help clarifying this question.If this question can be reworded to fit the rules in the help center, please edit the question.

I tried to edit your post but as you have written it, your notation is ambiguous and therefore cannot be edited. As such, your question has been marked for closure due to being unclear. –  heropup Jun 2 at 3:33
@chris, can you use MathJax to form your question? Is the function this: $f(x) = 9x^3\sqrt(c)-2x^5+\frac{x}{e^2}+11x$ or is it $f(x) = 9x^3\sqrt(c)-2x^5+e^{-2x}+11x$ Also tag your question as "homework", which I feel it is. –  tpb261 Jun 2 at 3:41
sorry the question is find the indefinite integral ((9x^3)(√x)) - 2x^5 + e^-2x + 11x past exam question my answer i got is =(x^2(e^2(12x^(5/2) -2x^4 +33)+3)) / 6e^2 –  user152431 Jun 2 at 3:53
@chris I've edited a few lines of the equation so you can know how LaTeX works. Now you continue my edit to avoid ambiguity or mistake. –  Tunk-Fey Jun 2 at 4:47