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In an isosceles $\triangle ABC$, side $AB$ and $AC$ are equal in length. There exists a point $D$ on the side $AB$. $\angle BAC$ is $\theta$. The side $AD$ is $2$ units smaller than $AC$. What is the generalized formula to calculate the side $CD$?

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I have tried this thing. I think that the formula would require some simple trignometry. – Vinay5forPrime May 28 '14 at 15:38
BD can be anything. – mercio May 28 '14 at 15:41
yes bd can be anything. – Vinay5forPrime May 28 '14 at 15:50
Use the Law of Cosines – Graham Kemp May 28 '14 at 16:01
I am asking for a proof in an algebraic form. Well I have also applied the law of cosines – Vinay5forPrime May 28 '14 at 16:02

This is a simple application of the cosine rule to the triangle $ACD$


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Ok I will verify and confirm it. – Vinay5forPrime May 29 '14 at 14:48
ok thank you this works. good job – Vinay5forPrime May 29 '14 at 15:02

You can draw a picture to convince yourself that the length of $BD$ does not depend on $\theta$. You will need to be given more information.

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