I need a proof that this equation has more than one solution for $p$ and $q$. $$p^{q-2}= 1024$$, where $q\in N, q>2$
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It seems that everybody so far missed the solution $p=1024$, $q=3$. :-) |
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How about $2^{10}$ and $4^5$? that gives you $p=2$ and $q=12$, or $p=4$ and $q = 7$. The easiest way to see this is just to factor $1024$ and see the possibilities... |
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