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How can I do this in Mathematica:

r=Range[0,20,0.13];
fr = HeavisideTheta[r];
data = somecoolfunctionsinmathematica[r,fr]

So that data now is in the form useful to Fit: {{r_1,fr_1},{r_2,fr_2},...}

Thanks!

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2 Answers 2

up vote 1 down vote accepted

This is the correct way to use Table if you prefer it to Map:

Table[{i, HeavisideTheta[10 - i]}, {i, 0, 20, 0.013}]
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I've found it, albeit syntactically a bit... involved (but I've seen a lot worse):

data = Table[{r[i], HeavisideTheta[10-r[i]]}, {r[i], Range[0, 20, 0.013]}]
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Map will do it: {#,HeavisideTheta[10-#]}&/@Range[0,20,0.013] –  Sasha Nov 9 '11 at 13:16
    
Also Transpose[{#, HeavisideTheta[10 - #]}]&[Range[0, 20, 0.013]]... –  J. M. Nov 9 '11 at 13:44
    
Funny how the (IMHO) much worse pops up in comments under my answer :) –  rubenvb Nov 9 '11 at 13:47
    
That's alright. IMHO taking a procedural approach when functional methods are available is a bit of a step backwards, but whatever, right? –  J. M. Nov 11 '11 at 2:04
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