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I really don't have any idea on how to solve this problem for homework. Can anyone help me?

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closed as off-topic by vonbrand, Daniel Rust, RecklessReckoner, Amzoti, SDevalapurkar May 6 at 0:38

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Do you need exactly three digits, or are two or one also acceptable? A general hint in a situation like this is to consider the size of the complement, the numbers containing only even digits. –  jdc May 5 at 23:09
$\operatorname{Count}(\text{at least 1 such}) = \operatorname{Count}(\text{all possible})-\operatorname{Count}(\text{none such})$ –  Graham Kemp May 5 at 23:17

1 Answer 1

Try counting those three digit numbers that only contain $0$, $2$, $4$, $6$, and $8$.

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PS: Remember to exclude numbers starting with 0. –  Graham Kemp May 5 at 23:18

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