Finding the coordinates of point on a parabola with a single point on an intersecting line

I have differential calculus problem where I must find the coordinates of a point C on a parabola. There is a point given which is D(8,4) and D is on a line that is intersecting with the parabola at C. Also, the line where there is the point D is perpendicular to the tangent of C.

This is the equation of the parabola:

f(x) = -x^2 + 4x + 2


This is coordinates of the single point given:

D (8,4)


What are the coordinates of C?

I am having trouble with the fact that there is only point given for the intersecting line.

Thank you for helping out!

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why is this tagged graph theory? :x) – anonymous Oct 24 '10 at 17:21

Using your differential calculus, you should be able to write the equation for the line tangent to the parabola at a given point on the parabola. So if $(x,y)$ satisfies $y=-x^2+4x+2$ what is the equation of the tangent line? Then you should be able to find the equation for the line perpendicular to the tangent at the point on the parabola. One of these perpendiculars will pass through $(8,4)$.