Three pirates were stranded on a desert island just outside of Pittsburgh. They came upon a treasure chest, which they opened and found to be full of oranges. Unfortunately they couldn't decide how to split them up, so they put all the oranges back in the chest. On the first afternoon, one pirate snuck away from the others and went to the chest. He separated the oranges into three equal piles. There was 1 extra so he gave it to a passing monkey. Then he ate one of the three piles and put the rest back in the chest. A short time later, the second pirate did the same thing. He separated the oranges into four equal piles. There were two extra oranges, which he gave to a passing monkey. He then ate one of the four piles and put the rest back. Later, the third pirate came to do the same thing. He split the oranges into five equal groups. He had 3 left which he gave to a passing money and ate 1 of the 5 equal piles and put the rest back. The next day the three pirates split the remaining. Each of the three pirates got 20 each.. How many oranges were in the chest originally? and how many did each pirate receive?
I listed out of the cases
.Treasure of oranges . Divide into 3 groups. . Gave away 1 . Ate 1/3 of oranges
Divide into 4 groups. Gave away 2 Ate 1/4 of oranges
Divide into 5. Gave away 3. Ate 1/5 oranges.
Split rest into 3 groups. Each got 20 oranges.
TO find how many I started with I started by working backwards.
They end up with 20 oranges each. Multiply by 3 = 60 oranges. One guy ate 1/5 so 75 oranges He gave away 3 so + 3 = 78
I get confused when I get to split into five groups. Do I count that again? Or do I go past the divide into 5 groups and straight to ate 1/4 of piles..
Basically, which answer would be correct for next?
Divide into 5 groups which would be : 78$\times$5= 390 oranges
Ate 1/4 of oranges which would be 1/4 of 78 which would = 104