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I am having a hard time getting to factor this binomial: I have tried other methods but they do not seem to work... ah well. $$4m^2-\frac{9}{25}.$$


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$(2m)^2-(\frac{3}{5})^2$ – pedja Oct 28 '11 at 19:31
If you're still stuck, try multiplying out $(4x - \frac{2}{3})(4x + \frac{2}{3})$ and focus on how the final answer of that calculation resembles your problem. – Michael Joyce Oct 28 '11 at 20:06
up vote 1 down vote accepted

If you mean $4m^2-\frac{9}{25}$, note that the second term is $(\frac{3}{5})^2$ and you have a difference of squares.

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I assume this is homework, so only ideas from me here.

Note that the formula is of the form $A^2-B^2$.

and we know that $A^2-B^2$ can be factored easily.

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If I do that, I get 4m^2-9/25... errr.... wha – naknode Oct 28 '11 at 19:51
weka, what exactly is the problem? $4m^2 = A^2$, so $A = 2m$... – The Chaz 2.0 Oct 29 '11 at 2:02

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