A spotlight has a parabolic cross section that is 8 ft wide at the opening and 2.5 ft deep at the vertex. How far from the vertex is the focus?
I'm getting 8/5 ft. Is this correct? Appreciated!
$1.6$ is the answer you seek. A convenient equation of the parabola is $5x^2=32y$. The line $x=y$ intersects the parabola at $(0\mid 0)$ -- trivial -- and at $(6.4\mid 6.4)$. One quarter of $6.4$ is $1.6$.