Take the 2-minute tour ×
Mathematics Stack Exchange is a question and answer site for people studying math at any level and professionals in related fields. It's 100% free, no registration required.

7=x√3

solve for x

DO NOT find the decimal answer of the √3 but keep it as a square root simplifying completely

(this is from a 30, 60, 90 triangle)

share|improve this question

closed as off-topic by Amzoti, T. Bongers, user127096, mookid, Sanath Devalapurkar Apr 8 at 2:16

This question appears to be off-topic. The users who voted to close gave this specific reason:

  • "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – Amzoti, T. Bongers, user127096, mookid, Sanath Devalapurkar
If this question can be reworded to fit the rules in the help center, please edit the question.

    
Be sure to include your approaches/thoughts. What have you tried so far for this problem? –  NasuSama Apr 8 at 1:29

1 Answer 1

After an exhaustive analysis, which took me fully into the realms of differential equations and general relativity, I have come to the tentative conclusion that $$x=\frac{7}{\sqrt{3}}$$ ...And I did that without converting to a decimal.

And if your teacher wants you to "clear the denominator" of the square root, that's really a silly thing to do so don't bother. (unless it will hurt your grade, of course - then multiply in the top and bottom by root 3).

share|improve this answer
    
+1 for humor$ $$ $ –  Mario Carneiro Apr 8 at 1:01
    
Although I understand the sentiment, don't be too quick to dismiss the value of learning to rationalize the denominator. The OP is obviously just starting his mathematical journey. If you have ever taught calculus, you must know that students who already know about this and are comfortable with it have no problem whatsoever computing the derivative of $1/\sqrt x$ from basics (as a limit), while those who never learned it struggle the most with this very elementary procedure. It is pedagogically invaluable. –  MPW Apr 8 at 1:09
    
@MPW It is useful. I just don't like it when ideas are presented in a vacuum. There's no point in making him/her change $1/\sqrt{3}$ to $\sqrt{3}/3$ if they're just doing algebra. It should be taught when it actually becomes relevant, such as in manipulating limits as you said. And I was being a little humorous obviously, no harm meant... –  user140943 Apr 8 at 1:13
    
The tag of algebraic geometry had me digging through SGA to no avail. Wish I had known this was a differential equations problem. –  PVAL Apr 8 at 1:17
    
@user140943: I understand your stance (and the jest). But I think making the student go through the steps, even if there doesn't seem to be a point, is how the procedure becomes second nature. It's how the student learns algebra. It should be taught at this early stage, not at the last moment when the student is already struggling with more advanced concepts. If the student can't already do basic algebra, there's little hope for mastering calculus. Math already has a bad name among students, and this sort of thing is often the underlying reason. –  MPW Apr 8 at 1:20

Not the answer you're looking for? Browse other questions tagged or ask your own question.