I'm having problem in getting the underlined statement from Gallian text:
Shouldn't the induction hypothesis be taken only on $n?$ But here the author also assumed the case for arbitrary field in induction hypothesis.
I'm having problem in getting the underlined statement from Gallian text:
Shouldn't the induction hypothesis be taken only on $n?$ But here the author also assumed the case for arbitrary field in induction hypothesis.
This is called Strong Induction. Assume for $P_1, \ldots P_n$ to be true and prove $P_{n+1}$ is true as well.
His assumption is for all fields and polynomials of degree less than $f(x)$.
If you want to use the Peano Postulates for the natural numbers as a foundation for your idea of induction, you need $n$ to be there somewhere. However, there are other basic foundations for induction - e.g. in set theory, within which we can build a model of the natural numbers.
Pure induction assumes a statement true for $n$ and shows that it follows for $n+1$ - then you need to establish the base case.
"Strong induction" assumes the truth of the statement for $1,2 \dots n$ and then proves it is true for $n+1$. Provided you have a way of talking about appropriate sets of numbers, this can be recast as follows. Let the proposition you are trying to prove be $P(n)$. Let $Q(n)$ be the proposition that $P(1), P(2) \dots P(n)$ are all true. If we can prove a base case and that $Q(n+1)$ follows from $Q(n)$ we have $Q(n)$ true, and this in turn implies that $P(n)$ is true.
In the case you cite, the induction is on the degree of the polynomial. It is a $Q$-type strong induction (all degrees less than or equal to $n$, where $f(x)$ has degree $n+1$). The hypothesis involves polynomials over "all fields" - but that is not a problem, provided we can deal with all fields at once in the proof. It doesn't impinge on the induction, which isn't on the size or nature of the field.