Take the 2-minute tour ×
Mathematics Stack Exchange is a question and answer site for people studying math at any level and professionals in related fields. It's 100% free, no registration required.

It makes sense conceptually to me I would just like this verified.

share|improve this question
    
The dot product can be distributed over addition: $\mathbf n\cdot(p\mathbf a+q\mathbf b)=p(\mathbf n\cdot\mathbf a)+q(\mathbf n\cdot\mathbf b)$... –  J. M. Oct 18 '11 at 1:12
add comment

1 Answer

up vote 4 down vote accepted

Yes! One way to check that two vectors are orthogonal is that their dot product is zero. So now you just need to algebraically check that if $\vec{v}\cdot\vec{a}=0$ and $\vec{v}\cdot\vec{b}=0$ then for any scalars $r,s$ we have $$\vec{v}\cdot(r\vec{a}+s\vec{b})=0.$$

share|improve this answer
    
Thanks! Seems blindingly obvious now. :D –  Jon Martin Oct 18 '11 at 2:10
add comment

Your Answer

 
discard

By posting your answer, you agree to the privacy policy and terms of service.

Not the answer you're looking for? Browse other questions tagged or ask your own question.