# Geometry/Algebra Question

My text states the following areas of two similar triangles: $$A_1 = \frac{1}{2}h_1b$$

$$A_2=\frac{1}{2}h_2e$$

$$\frac{A_1}{A_2}=\frac{\frac{1}{2}h_1b}{\frac{1}{2}h_2e}=\left(\frac{h_1}{h_2}\right) \left(\frac{b}{e}\right)=\left(\frac{b}{e}\right) \left(\frac{b}{e}\right)=\left(\frac{b^2}{e^2}\right)$$

I'm not following how they're getting:

$$\left(\frac{h_1}{h_2}\right) \left(\frac{b}{e}\right)=\left(\frac{b}{e}\right) \left(\frac{b}{e}\right)$$

I fear it's something painfully obvious.

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The triangles are similar, so the ratio of the heights is equal to the ratio of bases. –  Blue Mar 29 at 13:55
$$\frac{h_1}{h_2}=\frac{b}{e}$$