Some special manipulations involving finite sums. How to solve this sum?
$\displaystyle{\sum_{k=1}^{n}}\frac{1}{4k^2 - 1}$
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Some special manipulations involving finite sums. How to solve this sum? $\displaystyle{\sum_{k=1}^{n}}\frac{1}{4k^2 - 1}$ |
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The following problem below is for an infinite series, but if you can solve it you may be able to solve your problem above.
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Hint: Note that $$\frac{1}{4k^2-1}=\frac{\frac{1}{2}}{2k-1}-\frac{\frac{1}{2}}{2k+1}.$$ |
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