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I am not able to solve this question from chapter "Similar & Congruent Triangles" in my book.

Can some one help to calculate AC?


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WAit! According to your question BD + DC = DC + ED = CE = BC. But triangle BDE would then be a straight line, if you remember the triangle inequality! – Sawarnik Oct 13 '13 at 15:27

1 Answer 1

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Hint: $\triangle ABC \sim \triangle CEB \sim \triangle BDE$.

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hey thanks it worked ! i half thought of this but was fooled by the not-to-scale diagram!!! – schooler Oct 16 '11 at 8:54

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