# Letter and combination problem

I am having problem with the question below,

How many words can be formed out of the letters of the word "courage"?

This is a permutation problem if no letter is to be repeated. So you have $7$ letters and you want to form words with all $7$, so you should have $\frac{7!}{(7-7)!}=7!$. Alternatively, note that the first position could be filled in $7$ ways since you have $7$ letters, the second position $6$ ways since you have only $6$ letters now and so on. So you have $7!$ words you can form.