Take the 2-minute tour ×
Mathematics Stack Exchange is a question and answer site for people studying math at any level and professionals in related fields. It's 100% free, no registration required.

This question already has an answer here:

How would one calculate the probability of rolling a six (at least once) on seven dice? Would I be correct in proposing $1 - P(\text{no sixes})$ which is $1 - (5/6) ^ 7$?

share|improve this question

marked as duplicate by mookid, M Turgeon, Sami Ben Romdhane, Magdiragdag, user127096 Mar 26 '14 at 19:08

This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.

1 Answer 1

up vote 2 down vote accepted

Yes, that is correct, since "no sixes" is the complementary event to "at least one 6".

$$P(\text{at least one 6}) = 1 - P(\text{no 6 at all}) = 1 - (5/6)^7$$

If the question was "exactly one six" it would be different, but that does not seem to be the question.

share|improve this answer

Not the answer you're looking for? Browse other questions tagged or ask your own question.