Let X be the heigh of the father and Y the height of the son. The two random variables distributed with bivariate normal distribution, as demonstrated by Pearson in 1900. If E [X] = 68 inches and E [Y] = 69 inches, σx=σy = 2 and p = 0.5 : Find if the son of a father who has a height of 80 inches, is taller than his father.
Calculate: X|(Y=80)~Ν ( , ) (by using this formula http://prntscr.com/33si9s) Compare the mean that i will find above with 80 that is the height of the son.
I am not sure that this is the right solution.Any ideas? (Hints/Answers)