0
$\begingroup$

How do we show that, if $f:\mathbb{R}^n \rightarrow \mathbb{R}^m$ is homogeneous of degree $d > 1$, and if $f$ is differentiable at $0$, then $f'(0)$ is the zero map from $\mathbb{R}^n$ to $\mathbb{R}^m$?

$\endgroup$

1 Answer 1

1
$\begingroup$

For $|x|\to 0$, $$ f(x) = |x|^d f\left(\frac{x}{|x|} \right)= O(|x|^d) $$ because if $f$ is continuous it is bounded on the unit ball.

In particular, as $d>1$ $f$ is locally linear around 0 with derivative $f'(0) = 0$.

$\endgroup$

You must log in to answer this question.

Not the answer you're looking for? Browse other questions tagged .