If I choose 2 points on a line XY, each point being chosen according to the uniform distribution on XY, and the choices are being made independently. The line XY is now divided into 3 parts. What is the probability that they may be made into a triangle?
So they are asking to find the probability of the existence of a triangle with sides of length XP1, P1P2 and P2Y.
I read somewhere that it can only happen if and only if XP1 + P2Y > P1P2. Could someone explain why?
What does it mean by chosen according at the uniform distribution?