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Give a proof or counterexample.

Given reflexive relations $R$ and $S$ on $X$, $R\cap S$ is reflexive.

This would be true, correct?

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Please make the body of your post self-contained, instead of relying on the subject for key content. – Arturo Magidin Oct 6 '11 at 19:42
    
Well, do you have a proof, or do you have a counterexample? – Arturo Magidin Oct 6 '11 at 19:43
    
proofwiki.org/wiki/… – Martin Sleziak Oct 7 '11 at 10:24

If $R$ and $S$ are reflexive relations on a set $X$, then $(x,x)\in R$ and $(x,x)\in S$ for all $x\in X$, so $R\cap S$ is reflexive as well.

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Use proof by contradiction. Suppose that $R\cap S$ is not reflexive. Use definition of intersection to show a contradiction.

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